Topic: [SOLVED] Check if a string contains something other than \n

[papaface]

Hello,
How do I check if a string contains something other than \n.
E.g
If $string has "\n" in it, it will be rejected. But if it has "\nhello"  in it that will be okay.

Thanks

[jscix]

if the string contains just \n, the STRLEN($string), of that string should be 2. if it's greater than two, it contains other character, or.

or you could find the last position of \n, get all the text before and after it, and make sure each one has a value besides ""

etc.

[rarebit]

Oh sorry I thought it was for file parsing, so:

Code: [Select]

$s = "\n";
$n = strlen($s);
echo "len: ".$n."<br>";
$s = trim($s);
$n = strlen($s);
echo "len: ".$n."<br>";e.g. trim get's rid of '\n', but that won't work in your case...

Code: [Select]

if(strstr($s, "\n") && (strlen($s) > 1))Should work but not tried, other checks may be needed... i.e. if not contain!

[rarebit]

The length of "\n" should be 1, not 2. The '\' is a switch and ignored, ascii char 10...

[jesirose]

why not use trim() and then check the strlen?

[papaface]

Thanks for your advice people
At first I thought the \n and \rs were still in the string but they werent. so i just used:

Code: [Select]

if (strlen($value) == 0)
{
unset($domain[$key]);
} Instead.

Thanks

[corbin]

Just for the record, you could do something like this if you did want to find if \n was in a string.


$l1 = strlen($str);
$l2 = strlen(str_replace("\n", $str));
if($l1 != $l2) echo 'String contains \n';