[SOLVED] PHP to MySQL problem :(

Hey guys,

I'm having a problem sending data to a table in a MySQL db, i have other tables and php pages set up that are almost identical and work perfectly but for some reason this one refuses to work. I wonder if anyone can spot a school boy error?

thank you in advance for taking the time to read this.

<?php

  // Check if session is not registered , redirect back to login page.

  include('includes/checklogin.php');

  // Connect to server and select database

  include('includes/db_login.php');

  // Data sent from form, validated using js on the form itself

  // mysql_real_escape function used to deny sql injection attacks

  $softwareid =strip_tags(mysql_real_escape_string($_POST['softwaretitle']));

  $licencetypeid =strip_tags(mysql_real_escape_string($_POST['licencetype']));

  $key =strip_tags(mysql_real_escape_string($_POST['key']));

  $licences =strip_tags(mysql_real_escape_string($_POST['licences']));

  // Insert data into mysql

  $query="INSERT INTO tkeys (softwareid, licencetypeid, key, licences) VALUES('$softwareid', '$licencetypeid', '$key', '$licences')";

  $result=mysql_query($query);

  if (!$result) {

    die ("Could not query the database: <br />". mysql_error());

  }

  // If successfully insert data into database, displays message "Successful".

  if($result) {

    echo "Successfuly added <b> key</b> - add another?";

    echo "<br />";

    include('addlicence.php');

  } else {

    die ("Could not query the database: <br />". mysql_error());

  }

?>

the error im getting is:

Could not query the database:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key, licences) VALUES('92', '1', '9342j-nh923f-2n9f23-24g35', '3')' at line 1

but i cant find anything wrong with the syntax!! argh!

and also if this helps:

-- --------------------------------------------------------

--

-- Table structure for table `tkeys`

--

CREATE TABLE IF NOT EXISTS `tkeys` (

  `keyid` int(11) NOT NULL auto_increment,

  `softwareid` int(11) NOT NULL,

  `licencetypeid` int(11) NOT NULL,

  `key` varchar(100) default NULL,

  `licences` int(11) NOT NULL default '1',

  `isdeleted` tinyint(1) NOT NULL default '0',

  PRIMARY KEY  (`keyid`),

  KEY `softwareid` (`softwareid`),

  KEY `licencetypeid` (`licencetypeid`)

) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;

--

-- Constraints for dumped tables

--

--

-- Constraints for table `tkeys`

--

ALTER TABLE `tkeys`

  ADD CONSTRAINT `tkeys_ibfk_1` FOREIGN KEY (`softwareid`) REFERENCES `tsoftware` (`softwareid`),

  ADD CONSTRAINT `tkeys_ibfk_2` FOREIGN KEY (`licencetypeid`) REFERENCES `tlicencetype` (`licencetypeid`);

KEY is a mysql reserved word.  Change it and it should work.

well i feel foolish!!

thanks so much, quick fix!!

apreciated