Topic: Passing php variable to a function called in jquery ajax help

[TeddyKiller]

My code is below. I'm wanting to pass the php variable $db, to the function called.
The line where I'm having issues is
db: <?php echo $db ?>

Code: [Select]

$(document).ready(function() {
    $('#wait_1').hide();
    $('#drop_1').change(function(){
      $('#wait_1').show();
      $('#result_1').hide();
      $.get("func.php", {
        func: "drop_1",
        drop_var: $('#drop_1').val()
        db: <?php echo $db ?>
      }, function(response){
        $('#result_1').fadeOut();
        setTimeout("finishAjax('result_1', '"+escape(response)+"')", 400);
      });
        return false;
    });
});
How can it be done? Thanks

[CodeMaster]

You need to put quotes around the value and a comma on the line above. Like this:

Code: [Select]

$(document).ready(function() {
    $('#wait_1').hide();
    $('#drop_1').change(function(){
      $('#wait_1').show();
      $('#result_1').hide();
      $.get("func.php", {
        func: "drop_1",
        drop_var: $('#drop_1').val(),
        db: "<?php echo $db ?>"
      }, function(response){
        $('#result_1').fadeOut();
        setTimeout("finishAjax('result_1', '"+escape(response)+"')", 400);
      });
        return false;
    });
});