Author Topic: How to pass a random string into another variable  (Read 241 times)

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Offline myscriptingTopic starter

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How to pass a random string into another variable
« on: June 09, 2010, 07:17:27 PM »
I have two scripts. One is a tinyurl API and the other gnerates random strings. What I want to do it pass a random string into the tiny URL API script such that the tiny URL generated is always different

Code: [Select]
<?php

function createRandomPassword() { 

    
$chars "abcdefghijkmnopqrstuvwxyz023456789"
    
srand((double)microtime()*1000000); 
    
$i 0
    
$pass '' 

    while (
$i <= 7) { 
        
$num rand() % 33
        
$tmp substr($chars$num1); 
        
$pass $pass $tmp
        
$i++; 
    } 

    return 
$pass



// Usage 
$password createRandomPassword(); 

?>



<?php


//gets the data from a URL  
function get_tiny_url($url)  
{  
$ch curl_init();  
$timeout 5;  
curl_setopt($ch,CURLOPT_URL,'http://tinyurl.com/api-create.php?url='.$url);  
curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);  
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);  
$data curl_exec($ch);  
curl_close($ch);  
return $data;  
}

//test it out!
$new_url get_tiny_url('http://domain.com/?password);


echo $new_url

?>

where it says http://domain.com/?password i want the password value in the first script to be passed before a tiny url is generated

thanks