php array * with % (help request :p)

[lasse48]

hello guys , can you guys see any errors in this code`?

i cant seem to find it  :-\

 

<?php

$units_stats_1 = array(40, 35, 50);
$units_stats_2 = array($units_stats_1[0] * 50%, $units_stats_1[1] * 100%, $units_stats_1[2] * 100%);

echo $units_stats_2;


?>

 

i allso tryed to do :

echo $units_stats_2[0];

 

 

thanks 

 

[MadTechie]

i assume you mean this,

<?php

$units_stats_1 = array(40, 35, 50);
$units_stats_2 = array( $units_stats_1[0] * (1+(50/100)), $units_stats_1[1] * (1+(100/100)), $units_stats_1[2] * (1+(100/100)));

echo $units_stats_2[0]."<BR />\n";
echo $units_stats_2[1]."<BR />\n";
echo $units_stats_2[2]."<BR />\n";
?>

remove the 1+ if you do mean (40 x 50%) that = 20 and the 35 and 50 would remain unchanged

[lasse48]

thanks alot MadTechie , it worked like i wanted it to do now with your help 

[MadTechie]

Your welcome,

 

of course the 100/100 can be replaced with 1 (well 2 if you also remove the +1) i just added to make it clear..

 

if this is solved can you click solved (bottom left)

 

--MadTechie