Staff 4 on 4 off Rota

[TEENFRONT]

Hi Everyone!

 

Really stuck with this one.. Im midway through creating a "rota" for staff at work.. and it shows whos working that day, and who isnt.

 

For a "base" rota (unedited with no holidays/sickness etc) i need to populate the calendar i made with staff names on a 4 on 4 off basis. I was hoping php could loop round and pop the names in for me.

 

Here's whats i have so far:

 

$shifts1 = array("Day", "Night");
$shifts2 = array("Night", "Day");
$staffPair1 = array("Adam", "Ashley");
$staffPair2 = array("Dave", "Terry");

$thisMonth = date("F");
$daysThisMonth = date("t");

for ($i = 1; $i <= $daysThisMonth; $i++) {
$calGen .= "<div id=\"calendarDays\"><div>$i</div><div>$STAFF_ON_SHIFT</div></div>";
}

 

 

Pair1 work together, one is on DAYS, one is on NIGHTS for 4 days/nights then both are off for 4 days, Pair2 then steps in and works the same for 4 days/nights, then off for 4 days etc etc.

 

I need to echo $STAFF_ON_SHIFT which is who is on what shift on what date.

 

So for example a month would be like this:

 

Adam (D)

Ashley (N)

Terry (OFF)

Dave (OFF)

 

above x4 days - then

 

Adam (OFF)

Ashley (OFF)

Terry (D)

Dave (N)

 

above x4 days - then

 

Adam (N)

Ashley (D)

Terry (OFF)

Dave (OFF)

 

above x4 days - then

 

Adam (OFF)

Ashley (OFF)

Terry (N)

Dave (D)

 

First pair switches shifts round every other 4 so Adam is on nights and Ashley on Days then off for 4 days, then Adam is on days and Ashley on nights, same for pair2 (shift switch around)..

 

I know thats a lot to ask, but breaking it down looks "simple" lol.

 

Assign a shift to pair1 for 4 days

Pair 2 off for 4 days

 

Assign a shift to pair2 for 4 days

Pair 1 off for 4 days

 

Repeat above but swap shifts round for each pair (nights, days)

 

Any help?

 

MANY MANY THANKS!!!!!!