Jager Posted September 2, 2010 Share Posted September 2, 2010 Hi guys, i'm having trouble with making a order form for my school assignment, i'm trying to get it so that it gets the product number from one of the tables to show in a drop down box thingy any help would be greatly appricated. the code is below: <form name="Place an Order" method="post" action="order2.php "></center> <center><p>Enter the Product ID of the product you wish to purchase <a href="product.php" target="content">(cant remember? click here)</a>: <input name="ProductID" type="select" value="$query=mysql_query("SELECT ProductID FROM Products ORDER BY ProductName ASC") or die(mysql_error()); print("<select name=\"productid\">\n"); while ($row = mysql_fetch_row($query)) { printf("<option value=\"*" selected>*</option>\n", $row[0], $row[1]); } print("</select><br>");">"</p> <p>Customer ID <a href="Customer.php" target="content">(If you are not already a customer click here)</a>: <input name="CustomerID" type="text" value="Customer ID"></p> <p>Quantity: <input name="Quantity" type="text" value="99"></p> <input name="Place Order" type="submit" value="Place Order"> </center> </form> Quote Link to comment Share on other sites More sharing options...
Rifts Posted September 2, 2010 Share Posted September 2, 2010 trying something like this <?php mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); mysql_select_db(DB_DATABASE); if (!isset($_POST['whatever'])) { $q = mysql_query("SELECT * FROM table ORDER BY date DESC"); echo "<select name='whatever'>"; while ($row = mysql_fetch_assoc($q)) { echo '<option value="'.$row['whatever'].'">'.$row['whatever'].'</option>'; } echo "</select>"; }else { print_r($_SERVER); print_r($_POST); ?> Quote Link to comment Share on other sites More sharing options...
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