drop dow list for date only inserts year into database

[Lisa23]

Hi i have a drop down menu for date which is meant to insert all 3 values into a date column bt is only sending the year how can i fix it

 

<select name="date_of_birth">

    <option value="1">January

    <option value="2">February

    <option value="3">March

    <option value="4">April

    <option value="5">May

    <option value="6">June

    <option value="7">July

    <option value="8">August

    <option value="9">September

    <option value="10">October

    <option value="11">November

    <option value="12">December

</select>

<select name="date_of_birth">

    <option value="1">1

    <option value="2">2

    <option value="3">3

    <option value="4">4

    <option value="5">5

    <option value="6">6

    <option value="7">7

    <option value="8">8

    <option value="9">9

    <option value="10">10

    <option value="11">11

    <option value="12">12

    <option value="13">13

    <option value="14">14

    <option value="15">15

    <option value="16">16

    <option value="17">17

    <option value="18">18

    <option value="19">19

    <option value="20">20

    <option value="21">21

    <option value="22">22

    <option value="23">23

    <option value="24">24

    <option value="25">25

    <option value="26">26

    <option value="27">27

    <option value="28">28

    <option value="29">29

    <option value="30">30

    <option value="31">31

</select>

<select name="date_of_birth" id="year">

<?php

$year = date("Y");

for($i=$year;$i>$year-50;$i--)

{

if($year == $i)

echo "<option value='$i' selected>Current Year</option>";

else

echo "<option value='$i'>$i</option>";

}

?>

[kenrbnsn]

Fix your form. You're using the same name for each input, so only the last value is sent. Use different names.

 

Ken

[Lisa23]

yeah but then how do i sent into column because i have like this

 

mysql insert '$_POST[date_of_birth]' do i change that to what if all three will have different names??? i want all all to go into same column cz thers the month year and date id i give differnt name how do i make it all go into same column???

[kenrbnsn]

You would concatenate the POSTed values in the query. For example, in your form:

<?php
$months = array('','January','February','March','April','May','June','July','August','September','October','November','December');
echo '<select name="month_of_birth">';
for ($i=1;$i<13;++$i) {
   echo '<option value="' . sprintf("%02d",$i) . '">' . $months[$i] . '</option>';
}
echo '</select>';
echo '<select name="day_of_birth">';
for ($i=1;$i<32;++$i) {
   echo '<option value="' . sprintf("%02d",$i) . '">' . $i . '</option>';
}
echo '</select>';
echo '<select name="year_of_birth">';
$year = date("Y");
for ($i = $year;$i > $year-50;$i--) {
   $s = ($i == $year)?' selected':'';
   echo '<option value="' . $i . '" ' . $s . '>' . $i . '</option>';
}
?>

Then in your processing script:

<?php
$date_of_birth = $_POST['year_of_birth'] . '-' . $_POST['month_of_birth'] . '-' . $_POST['day_of_birth'];
$q = "insert into tbl set column_name = '$date_of_birth'";
?>

 

Note: syntax not checked for errors.

 

Ken

[Lisa23]

sorry but my insert method is like this so i dnt really know how to implement urs into it??

 

mine

mysql_query("INSERT INTO driversnew (id, name, location, date_of_birth, car_number,
   favourite_track, least_favourite_track, achievements, sponsors, email, image, display)
VALUES ('$_POST[id]', '$_POST[name]', '$_POST[location]','$_POST[date_of_birth]','$_POST[date_of_month]','$_POST[date_of_year]','$_POST[car_number]','$_POST[favourite_track]', '$_POST[least_favourite_track]','$_POST[achievements]', '$_POST[sponsors]','$_POST[email]', '$image_name','0')");
}

yours

<?php
$date_of_birth = $_POST['year_of_birth'] . '-' . $_POST['month_of_birth'] . '-' . $_POST['day_of_birth'];
$q = "insert into tbl set column_name = '$date_of_birth'";
?>

[kenrbnsn]

Mine was just an example, since I didn't know yours.

 

Here's yours with my example:

<?php
$date_of_birth = $_POST['year_of_birth'] . '-' . $_POST['month_of_birth'] . '-' . $_POST['day_of_birth'];
$q = "INSERT INTO driversnew (id, name, location, date_of_birth, car_number,
   favourite_track, least_favourite_track, achievements, sponsors, email, image, display)
VALUES ('$_POST[id]', '$_POST[name]', '$_POST[location]','$date_of_birth','$_POST[car_number]','$_POST[favourite_track]', '$_POST[least_favourite_track]','$_POST[achievements]', '$_POST[sponsors]','$_POST[email]', '$image_name','0')";
$rs = mysql_query($q) or die("Problem with the query: $q<br>" . mysql_error());
?>

BTW, you really should be validating the input from your form, or you will run into problems.

 

Ken

[Lisa23]

it post everything except the date???

[kenrbnsn]

Like I said "syntax not checked for errors" -- I left out the "</select>" tag at the end of the last <select>.

 

When I have trouble getting data from form, I put

<?php
echo '<pre>' . print_r($_POST,true) . '</pre>';
?>

at the start of the processing script. This will show the data that your form is sending. It can be very helpful.

 

Ken

[Lisa23]

this come up bt still doenst sent date

Array

(

    [name] => phpfreaks

    [location] => uyfuy

    [month_of_birth] => 01

    [day_of_birth] => 01

    [year_of_birth] => 2010

    [car_number] => carnumber

    [favourite_track] => uyf

    [least_favourite_track] =>

    [achievements] =>

    [sponsors] =>

    => newyork@hotmail.com

    [verif_box] => 4342

    [submit] => Submit

)

 

[kenrbnsn]

Can you show us you mysql insert statement?

 

Ken

[Lisa23]

$q = "INSERT INTO driversnew (id, name, location, date_of_birth, car_number,

  favourite_track, least_favourite_track, achievements, sponsors, email, image, display)

VALUES ('$_POST[id]', '$_POST[name]', '$_POST[location]','$date_of_birth','$_POST[car_number]','$_POST[favourite_track]', '$_POST[least_favourite_track]','$_POST[achievements]', '$_POST[sponsors]','$_POST', '$image_name','0')";

$rs = mysql_query($q) or die("Problem with the query: $q<br>" . mysql_error());

 

and the form

<?php
$months = array('','January','February','March','April','May','June','July','August','September','October','November','December');
echo '<select name="month_of_birth">';
for ($i=1;$i<13;++$i) {
   echo '<option value="' . sprintf("%02d",$i) . '">' . $months[$i] . '</option>';
}
echo '</select>';
echo '<select name="day_of_birth">';
for ($i=1;$i<32;++$i) {
   echo '<option value="' . sprintf("%02d",$i) . '">' . $i . '</option>';
}
echo '</select>';
echo '<select name="year_of_birth">';
$year = date("Y");
for ($i = $year;$i > $year-50;$i--) {
   $s = ($i == $year)?' selected':'';
   echo '<option value="' . $i . '" ' . $s . '>' . $i . '</option>';
}
echo '</select>';
?>

[kenrbnsn]

Did you put this line before the query:

<?php
$date_of_birth = $_POST['year_of_birth'] . '-' . $_POST['month_of_birth'] . '-' . $_POST['day_of_birth'];
?>

Put an

<?php
echo $q . "<br>";
?>

and see what is displayed.

 

Ken

[Lisa23]

yeah i have that line this what comes up

$date_of_birth = $_POST['year_of_birth'] . '-' . $_POST['month_of_birth'] . '-' . $_POST['day_of_birth'];

 

INSERT INTO driversnew (id, name, location, date_of_birth, car_number, favourite_track, least_favourite_track, achievements, sponsors, email, image, display) VALUES ('', 'tv', 'location','2010-01-01','carnumber','', '','', '','newyork@hotmail.com', '','0')

[kenrbnsn]

Your query has the correct information in the correct place. Why do you think it's not being inserted?

 

Ken

[Lisa23]

i have this line do u think i need to modify in a way too??

 

$date_of_birth = stripslashes($date_of_birth);

[kenrbnsn]

No. The stripslashes function will only affect variable whose values contain a backslash.

 

It might be best to post what your code currently looks like. Also post the format of your database table, as there could be a problem with the datatype of the "date_of_birth" column.  I assumed it is a DATE type.

 

Ken

[Lisa23]

ok is posting now but i have this echo back to display bck but it doesnt display back the date

 

    echo "<td>" . $_POST['date_of_birth'] . "</td>";

 

and also this one that send to email doesnt display the date on the email

 

$message = "
	Name:					$name  \n

[kenrbnsn]

There is no "date_of_birth" in the $_POST array. You would have to echo the variable $date_of_birth instead. Probably the same for the email message.

 

Ken

[Lisa23]

on the email i have like this still doesnt wrk

 

$message = "

	DoB:				$date_of_birth  \n

	Email:					$email \n";

 

ohh and on the form is how do i keep the date after refresh i know how to do on a normal input text but on tha form is it possible??