Function with Time not returning

[rahulkadukar]

<?php

function time_convert($l_timestamp)
  {
    $l_timestamp = $l_timestamp * 86400;
    $time = date('Y-m-d',$l_timestamp);
    echo(date('Y-m-d',$l_timestamp));          //This does
    return (date('Y-m-d',$l_timestamp));      //This does not work
    return $time;         // This does not work
    echo $time;          //This does not work
  }
  
time_convert(32155.0);
?>

 

Can anyone help me, I am not getting the return parameter as I want

[PaulRyan]

When you are returning a value, you must echo the function like the following to get any output.

echo time_convert(32155.0);

Use that instead of just

time_convert(32155.0);

 

Then change the function to...

  function time_convert($timeStamp) {
    $timeStamp = $timeStamp * 86400;
    $converted = date('Y-m-d',$timeStamp);
    return $converted;         // This does not work
  }

 

Tell me how it goes bud.

 

Regards, Paul.

[rahulkadukar]

Sorry for making such a silly mistake, but my requirement is like this

 

1. I have time in a certain format which I am reading from a file

2. I want to convert it using the Function

3. Then want to write the converted output to a separate file

 

The problem is the Function is not returning the converted value.

[PaulRyan]

I see what you mean, but my solution should work tbh...

 

<?php

  function time_convert($timeStamp) {
    $timeStamp = $timeStamp * 86400;        // Set the timestamp
    $converted = date('Y-m-d',$timeStamp);  // Convert the timestamp
    return $converted;                      // Return the timestamp
  }

  $convertedTime = time_convert(32155.0);
?>

 

$convertedTime if the returned value that can be used how you wish.

You can write that variable to the file and it will work.

 

Regards, Paul.

[rahulkadukar]

Got it I was passing $data while the variable was stored in $date, I was correct all along but was passing the wrong value.  Anyway thanks for all your help 

[PaulRyan]

Not a problem buddy, mistakes will be made