StefanRSA Posted September 30, 2010 Share Posted September 30, 2010 I am trying to populate different select boxes from a DB lookup... I look in two table.... One to the catid and then all subcats per catid... I am not sure how this should work... My code as follow: $catkey='1,4,5'; $query = "SELECT adcat.id AS catid, adsubcat.name AS subname, adsubcat.id AS subid, adsubcat.linkname AS sublink, adcat.clinkname AS clink, adcat.name AS catname FROM adsubcat JOIN adcat ON adcat.id=adsubcat.catid WHERE adsubcat.catid IN($catkey) ORDER BY adsubcat.name ASC"; $result = mysql_query($query) or die(mysql_error()); $num_rows = mysql_num_rows($result); while ($row = mysql_fetch_assoc($result)){ $catid=$row['catid']; $subid=$row['subid']; $subname=$row['subname']; ////////////////////////////////////////////////////////////////////////////// STUFF I AM NOT SURE OF STARTS HERE // The loop should now echo at the start of every echo $catname.'<select id="subcat" multiple="multiple" name="sub[]"><option value="" >ALL SUB-CATEGORIES</option>'; ////And for every subcat per id it should echo '<option value="'.$subid.'">'.$subname.'</option>'; ///// The loop per Catid should end with echo '<select>'; ////////////////////////////////////////////////////////////////////////////// STUFF I AM NOT SURE OF ENDS HERE } I want it then to print out as follow: CAT 1 <select id="catid1" multiple="multiple" name="cat1[]"> <option value="0" >ALL SUB-CATEGORIES FOR Cat 1</option> <option value="1" >Subname 1.1</option> <option value="2" >Subname 1.2</option> </select> CAT 4 <select id="catid4" multiple="multiple" name="cat4[]"> <option value="0" >ALL SUB-CATEGORIES FOR Cat 4</option> <option value="4" >Subname 2.4</option> <option value="7" >Subname 2.7</option> </select> CAT 5 <select id="catid5" multiple="multiple" name="cat5[]"> <option value="0" >ALL SUB-CATEGORIES FOR Cat 5</option> <option value="65" >Subname 5.65</option> <option value="34" >Subname 5.34</option> </select> Quote Link to comment Share on other sites More sharing options...
StefanRSA Posted September 30, 2010 Author Share Posted September 30, 2010 Anybody? Quote Link to comment Share on other sites More sharing options...
StefanRSA Posted September 30, 2010 Author Share Posted September 30, 2010 Fixed it the long way around: $catquery="SELECT * FROM adcat WHERE id IN($catkey) ORDER BY name ASC"; $catresult = mysql_query($catquery) or die(mysql_error()); while($crows = mysql_fetch_array($catresult)){ $thisid=$crows['id']; $catname=$crows['name']; echo '<p>'.$catname.'<br> <select style="display: none;" id="CAT'.$thisid.'" multiple="multiple" name="sub'.$thisid.'[]"> <option value="0" >ALL SUB-CATEGORIES</option>'; ///////////////// ECHO SELECTBOX START HERE $query = "SELECT adcat.id AS catid, adsubcat.name AS subname, adsubcat.id AS subid, adsubcat.linkname AS sublink, adcat.clinkname AS clink, adcat.name AS catname FROM adsubcat JOIN adcat ON adcat.id=adsubcat.catid WHERE catid='$thisid' ORDER BY adsubcat.name ASC"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ $catid=$row['catid']; $subid=$row['subid']; $subname=$row['subname']; echo '<option value="'.$subid.'">'.$subname.'</option>'; } echo '</select></p><div style="height:10px;width:100%:clear:both;"></div>';///////////////// ECHO SELECTBOX END HERE } Quote Link to comment Share on other sites More sharing options...
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