Mr.Canuck Posted October 4, 2010 Share Posted October 4, 2010 I currently have a file upload form that uploads images to a folder on my server called "attachments". This is the directory path: www.mysite.com/docs/attachments/ However, I want the images to upload to www.mysite.com/data/attachments/ instead. I have included the relevant part of the PHP below. I have tried changing this: $cur_dir = $cur_dir."/".$dir; to this: $cur_dir = $cur_dir."www.mysite.com/data/attachments/".$dir; and changing this: $dirs = explode("/","attachments//"); to this: $dirs = explode("www.mysite.com/data/","attachments//"); and also changing this: $_values[$file[0]."_real-name"] = "attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; to this: $_values[$file[0]."_real-name"] = "www.mysite.com/data/attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; But nothing has worked so far. Any suggestions would be appreciated. foreach($files[$form] as $file){ $str = $file[1]; if (eval("if($str){return true;}")) { $_values[$file[0]] = $_FILES[$file[0]]["name"]; $dirs = explode("/","attachments//"); $cur_dir ="."; foreach($dirs as $dir){ $cur_dir = $cur_dir."/".$dir; if (!@opendir($cur_dir)) { mkdir($cur_dir, 0777);}} $_values[$file[0]."_real-name"] = "attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; copy($_FILES[$file[0]]["tmp_name"],$_values[$file[0]."_real-name"]); @unlink($_FILES[$file[0]]["tmp_name"]); }else{ $flag=true; if ($_isdisplay) { //$ExtFltr = $file[2]; //$FileSize = $file[4]; if (!eval("if($file[2]){return true;}")){echo $file[3];} if (!eval("if($file[4]){return true;}")){echo $file[5];} $_ErrorList[] = $file[0]; } } } Quote Link to comment Share on other sites More sharing options...
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