RLJ Posted October 10, 2010 Share Posted October 10, 2010 Hi, I have an html form in "send.htm" that sends data to "retrieve.php" with the following structure: send.htm: <html> <body> <form method="post" action="retrieve.php" <select id='select' name='select' > <option>option1</option> <option>option2</option> <option>option3</option> <option>etc...</option> </select> <input type="submit"> </form> </body> </html> retrieve.php: <?php $selectedoption = $_POST['select']; print" <html> <body> <select id='select' name='select' > <option>option1</option> <option>option2</option> <option>option3</option> <option>etc...</option> </select> </body> </html> "; ?> How do I specify that the select menu in retrieve.php should have the option selected that was chosen from the select menu in send.htm? I'm guessing this is probably quite straightforward, but I can't quite work it out. Please help! Thanks. Quote Link to comment Share on other sites More sharing options...
PaulRyan Posted October 10, 2010 Share Posted October 10, 2010 You need to set the value of the an <option> Like <option value='1'>option1</option>... that will then post the selected option to the next page to be used how you want. Regards, Paul. Quote Link to comment Share on other sites More sharing options...
Pikachu2000 Posted October 10, 2010 Share Posted October 10, 2010 As PaulRyan said, your <option> tags need a name= attribute for the <select> to pass the value properly. I find it easier to build <select>s from an array, especially when making a "sticky" form. Here's a basic demo. It's the same principle as building the <select> from a database query result. echo '<form method="post">'; $select = array( 1 => 'value 1', // starts the indices at 1 instead of 0 'value 2', 'value 3', 'value 4', 'value 5' ); echo '<select name="name">\n'; foreach( $select as $k => $v ) { echo "<option value=\"$k\""; echo $k == $_POST['name'] ? ' selected="selected"' : ''; // pre-selects the option if the value matches what was submitted echo ">$v</option>\n"; } echo '</select>'; echo '<input type="submit" value="submit" name="submit"></form>'; Quote Link to comment Share on other sites More sharing options...
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