Jump to content

Variable doesn't pass data into database


ipPHPadmin

Recommended Posts

Hello all,

 

I can't get the data store in the $ART_ID variable to pass into the database.  The original $Artisan variable is set up like this: 1. Artisan Name.  So the explode is taking just the number. If I put an echo after the explode and the $ART_ID variable it outputs the correct information but it doesn't store in the database as that data.  The query is in correct order too.

Thanks in advance. 

 

 

 

$CType_Type = $_REQUEST["CTYPE_Type"];

$Artisan = $_REQUEST['Artisan'];

$Quantity = $_POST['Quantity'];

$HAnswer1 = $_POST["HAnswer1"];

$HAnswer2 = $_POST["HAnswer2"];

$HAnswer3 = $_POST["HAnswer3"];

$HAnswer4 = $_POST["HAnswer4"];

 

$break = explode(".", $Artisan);

$ART_ID = $break[0];

 

if(!$Quantity)

{

die('Quantity field is empty. Please enter the quantity of handicrafts made.');

}

else

{

 

$ctypeQuery = mysql_query("SELECT CTYPE_ID FROM CraftType WHERE CTYPE_Type = '".$CType_Type."'");

 

while($row = mysql_fetch_array($ctypeQuery))

{

$CTYPE_ID = $row["CTYPE_ID"];

 

$sql = ("INSERT INTO Handicraft VALUES (`HANDI_ID`, '".$Quantity."', 'NULL', '".$CTYPE_ID."', '".$ART_ID."', 'NULL', '1')");

 

if(!mysql_query($sql))

{

die('Error inserting Handicraft Type into table: ' . mysql_error());

}

else

                { -----data in this section doesn't affect the rest of the code---- }

      }

}

Link to comment
Share on other sites

$sql = ("INSERT INTO Handicraft VALUES (`HANDI_ID`, '".$Quantity."', 'NULL', '".$CTYPE_ID."', '".$ART_ID."', 'NULL', '1')");

 

try changing it to

 

$sql = "INSERT INTO Handicraft VALUES (`HANDI_ID`, '$Quantity', NULL, '$CTYPE_ID', '$ART_ID', NULL, 1)";

 

OR

keeping it simple omit null values but be sure to include the column names when u do so

like

 

insert into (col_name1,col_name2,col_name4,col_name6) values ('blah','blah','blah','blah')

Link to comment
Share on other sites

Alright, first off, thanks for the timely responses devilinc.  As for your questions, I am trying to insert just the "1" part and the data type of the database field is correct.  I tried what you said in your most recent post and it worked! Do you have any idea why removing the " and . would make it work correctly?

 

Thanks again for the help.

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.