RichyVn Posted December 9, 2010 Share Posted December 9, 2010 I need some help with updating the database table with the correct selection from that box. I have a dropdown box. This is actually a list from the images in a curtain directory. here the code I used: <?php $dhandle = opendir('../images/Vessels/'); $files = array(); if ($dhandle) { // loop through all of the files while (false !== ($fname = readdir($dhandle))) { if (($fname != '.') && ($fname != '..') && ($fname != basename($_SERVER['PHP_SELF']))) { $files[] = (is_dir( "./$fname" )) ? "(Dir) {$fname}" : $fname; } } closedir($dhandle); } So when inserting a new record I can use the dropdownbox to populate the correct field. Database: Id, Vesselname, Image, more, andmore There is a section where an authorized user can upload an image to the directory. This image will then be available in dropdown when the need to add a new vessel (in this case) The problem that I have is, when I later what to update the vessel, I want that same dropdownbox to be showing the correct imagename as "selected". How can I do that? This is what I have been expirementing with sofar: <?php require_once('../Connections/bgf_db.php'); ?> <?php $dhandle = opendir('../images/Vessels/'); $files = array(); $selectedFile = "mare.jpg"; if ($dhandle) { // loop through all of the files while (false !== ($fname = readdir($dhandle))) { if (($fname != '.') && ($fname != '..') && ($fname != basename($_SERVER['PHP_SELF']))) { $files[] = (is_dir( "./$fname" )) ? "(Dir) {$fname}" : $fname; } } closedir($dhandle); } if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } $MyFile_Recordset1 = "no-picture.jpg"; if (isset($selectedFile)) { $MyFile_Recordset1 = $selectedFile; } mysql_select_db($database_bgf_db, $bgf_db); $query_Recordset1 = sprintf("SELECT vessels.Name, vessels.Image FROM vessels WHERE vessels.Image = %s", GetSQLValueString($MyFile_Recordset1, "text")); $Recordset1 = mysql_query($query_Recordset1, $bgf_db) or die(mysql_error()); $row_Recordset1 = mysql_fetch_assoc($Recordset1); $totalRows_Recordset1 = mysql_num_rows($Recordset1); $selectedFile = $row_Recordset1['Image']; ?> <select name="NameHere"> <option value="<?php echo $selectedFile?>" <?php if (!(strcmp($selectedFile, $row_Recordset1['Image']))) {echo "selected=\"selected\"";} ?>><?php echo $selectedFile ?> </option> <?php // Now loop through the files, echoing out a new select option for each one foreach( $files as $fname ) { echo "<option value=\"$fname\">{$fname}</option>\n"; } echo "</select>\n"; ?> Quote Link to comment Share on other sites More sharing options...
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