Integer define ;S

[quelle]

Ive got a simple function that's counting percentages of the results, and what I want is when the first line does $variable / 100 - to go on 2 decimals(ex. 0.72142141 what I want is to write 0.72).

 

function postotak(){
$p = $bodovi / 100;
$postotak = $p * 100;

[BlueSkyIS]

round() function?

[quelle]

the round function goes on an integer as i read 5 minutes ago, but if there is no other way it not a big deal rly ... (for ex. if $score = 60, $p=$score/110, $postotak=$p*100, $postotak = 54%). Btw my

function postotak(){
$p = $bodovi / 100;
$postotak = $p * 100;
$postotak = $postotak + "%";

return $postotak;
}

It does return nothing why 

[BlueSkyIS]

because $bodovi is not defined in your function.

 

and this should be...

 

$postotak = $postotak . "%";

[quelle]

yeah thanks for that $postotak = $postotak . "%"; figured it now. The variable isnt defined but i used global $bodovi outside of function, shouldnt be same ?

[BlueSkyIS]

you must declare global $bodovi; inside the function, but better to just pass it to the function instead of relying on globals.

 

 

[quelle]

hmm lol look at this

function postotak($bodovi){
$p = $bodovi / 100;
$postotak = $p * 100;
$postotak = $postotak . "%";

return $postotak;
}

Warning: Missing argument 1 for postotak(), called in D:\xampp\htdocs\vjezbe\kviz - seica\rezultati.php on line 35 and defined in D:\xampp\htdocs\vjezbe\kviz - seica\rezultati.php on line 28 - THIS IS THE ERROR I GOT BY PASSING THE VARIABLE TO THE FUNCTION

 

28th line is the first line of this function

[BlueSkyIS]

<?php

function postotak($input_var){
$p = $input_var / 100;
$postotak = $p * 100;
$postotak = $postotak . "%";

return $postotak;
}

echo postotak($bodovi);

?>

[quelle]

ty