Cookie is not created and Page is not redirect properly....

ankit.pandeyc012 · December 25, 2010

<?php
require_once('upper.php');
$error_msg='';
if(!isset($_COOKIE['LoginIdCookie'])){
if(isset($_POST['submit']))
{
require_once('database.php');
$LoginId=mysqli_real_escape_string($dbc,trim($_POST['LoginId']));
$Password=mysqli_real_escape_string($dbc,trim($_POST['Password']));
if((!empty($LoginId)) && (!empty($Password))){
$query="SELECT * FROM registration WHERE LoginId='$LoginId' AND Password=SHA('$Password') AND Flag='A'";
$result=mysqli_query($dbc,$query) or die('Not Connected');
if(mysqli_num_rows($result)==1)		
{
$row=mysqli_fetch_array($result);
setcookie('LoginIdCookie',$row['LoginId']);
//$home_url = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . '/index1.php';
header('Location: index1.php');
}
else{
echo 'Enter right UserName/Password combination or You may not approved yet. ';
echo '<a href="ForgetPassword.php">Can\'t access your account?"</a>';
}}
else{
echo' Fill all fields';
}
}}
?>
<html>
<title>Log In</title>
<body>
<?php
if(empty($_COOKIE['LoginIdCookie']))
{
echo $error_msg;
?>
<form method="post" action="<?php echo $_SERVER['PHP_SELF'] ;?>" >
<div class="LoginValidator">
<fieldset>
<legend>
Log In</legend><table><tr><td>
<label for="username">User Name :</label><br/><br/></td>
<td><input type="text" name="LoginId"><br/><br/></tr>
<td><label for="password">Password :</label></td>
<td><head>
   <div id="divMayus" style="visibility:hidden">Caps Lock is on.</div>
   <SCRIPT language=Javascript>

function capLock(e){
kc = e.keyCode?e.keyCode:e.which;
sk = e.shiftKey?e.shiftKey:((kc == 16)?true:false);
if(((kc >= 65 && kc <= 90) && !sk)||((kc >= 97 && kc <= 122) && sk))
  document.getElementById('divMayus').style.visibility = 'visible';
else
  document.getElementById('divMayus').style.visibility = 'hidden';
}

</SCRIPT>
   </HEAD>

<input onkeypress='return capLock(event)' type="password" name="Password"><br/></td></tr></table>
<input type="submit" name="submit" value="Login" class="Login_button">
</fieldset>

</div>
</form>

<?php 
}
else{
echo 'You are logged in as '.$_COOKIE['LoginIdCookie'];
}
require_once('lower.php');
mysqli_close($dbc);
?>

HI friends..........

In above code when I enter wrong user name or password, it displays error msg properly but problem is that when i enter right user name and password instead to redirect to index1.php it displays LoginPage again..........

I think cookie is not created as well..........

I can't understand where is problem???????/

Plz help me....................

dragon_sa · December 25, 2010

try to echo $row['LoginId'] after the query and see if it gives you a result also the php manual says to put cookie name in double quotes.

eg setcookie("LoginIdCookie",$row['LoginId']);

ankit.pandeyc012 · December 25, 2010

Sir,

My original code properly works on my local system i.e. in windows XP but when i upload it in my Linux Server it creates problem.......

I don't know what is wrong??????////

dragon_sa · December 25, 2010

This will show you if the cookie is set

[print_r($_COOKIE);/php]

ankit.pandeyc012 · December 25, 2010

Ohhhhh

I got the main problem.......

Cookie is not setting in linux server actually but i don't know why it is so?????????

Is there anyone??????

PFMaBiSmAd · December 25, 2010

For debugging purposes, add the following two lines of code immediately after the line with your first opening php tag, and tell us if any php detected errors are displayed -

ini_set("display_errors", "1");
error_reporting(-1);

.josh · December 25, 2010

you said it works on localhost but on on a remote server...is your database and connection info the same on the remote server as it is on your localhost, same user/pw stored in db, etc..?

ankit.pandeyc012 · December 26, 2010

Sir, All passwords are set well and if I did this mistake then it should displayed an error.

But there is no error .............

ankit.pandeyc012 · December 26, 2010

For debugging purposes, add the following two lines of code immediately after the line with your first opening php tag, and tell us if any php detected errors are displayed -
ini_set("display_errors", "1");
error_reporting(-1);

Sir it not displayed any error.........

As I say it properly works on my local computer but when upload it in my linux server it creates problem.. I already checked username and password of database................

dragon_sa · December 26, 2010

what if you try this on a blank php page on the linux server

<?php
$value='my test cookie';
setcookie("TestCookie", $value);
print_r($_COOKIE);
?>

See if this prints out your newly set cookie

PFMaBiSmAd · December 26, 2010

I'm going to guess that your code is actually redirecting to index1.php, but that index1.php is redirecting back to the page you posted in this thread.

Have you actually checked in your bowser if the cookie exists and what value is in it? I suspect it is getting created with an empty() value and the code is doing what it is supposed to be doing (skipping the login code if the cookie isset() but displaying the login form if the value is empty().) You need to check what $row['LoginId'] actually contains. Either it is a value that the empty() function considers empty OR your column LoginId does not exist (possibly because you are on a case-sensitive operating system and the capitalization in your table is not exactly LoginId.)

ankit.pandeyc012 · December 27, 2010

what if you try this on a blank php page on the linux server
<?php
$value='my test cookie';
setcookie("TestCookie", $value);
print_r($_COOKIE);
?>
See if this prints out your newly set cookie

Thanks for reply.

but your above code displays "Array()".

I think cookie is not generated yet.

Plz help........

ankit.pandeyc012 · December 27, 2010

I'm going to guess that your code is actually redirecting to index1.php, but that index1.php is redirecting back to the page you posted in this thread.

Have you actually checked in your bowser if the cookie exists and what value is in it? I suspect it is getting created with an empty() value and the code is doing what it is supposed to be doing (skipping the login code if the cookie isset() but displaying the login form if the value is empty().) You need to check what $row['LoginId'] actually contains. Either it is a value that the empty() function considers empty OR your column LoginId does not exist (possibly because you are on a case-sensitive operating system and the capitalization in your table is not exactly LoginId.)

Thanks Sir,

What you said is right but i think it is problem of cookie because below code displays "Array()".
<?php
$value='my test cookie';
setcookie("TestCookie", $value);
print_r($_COOKIE);
?>
I want to tell I have same database in my local compuetr also.

Previously, same program runs on linux server properly but not now...............

Now what I have to do?????

Help me plzzzzzzzzzzzzzz

PFMaBiSmAd · December 27, 2010

Did you refresh the page with the code on it that dragon_sa posted, because the $_COOKIE variable is set when the browser sends the cookie with the HTTP request, not when you execute a setcookiei() statement.

Any chance you have disabled cookies in your browser for the domain you are testing this on?

ankit.pandeyc012 · December 27, 2010

Did you refresh the page with the code on it that dragon_sa posted, because the $_COOKIE variable is set when the browser sends the cookie with the HTTP request, not when you execute a setcookiei() statement.

Any chance you have disabled cookies in your browser for the domain you are testing this on?

Sir,

I upload this code. After that I try to login by login page and then after I execute dragon_sa code and it again displays "Array()"...

thx for replying but I don't get solution yet.........

Help plzzzzzzzzzzzzz

dragon_sa · December 27, 2010

instead of print_r($_COOKIE);

use

echo $_COOKIE["TestCookie"];

see if that gives you the value we set in the example code I posted

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Cookie is not created and Page is not redirect properly....

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