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How to send multiple variables into database?


dwex

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This will only send 1 goggles information into the database but I have a "adding" page that can actually add more than 1 goggles at once. I have no idea how to go about  saving multiple goggle's information using array or loop.

 

 

$name= $_POST['goggles_name'];
$price = $_POST['goggles_price'];
$des = $_POST['goggles_description'];
$file = $_FILES['goggles_image']['name'];
$chkbox = $_POST['upload'];
$id = $_POST['goggles_id'];


$query = "UPDATE goggles SET goggles_name = '$name' , goggles_price = '$price' ,goggles_description = '$des' WHERE goggles_id ='".$id."' "; 
$result = mysqli_query($link, $query) or die(mysqli_error($link));

 

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You can ask the user how many items they wish to enter, then dynamically create that many form boxes, then just use a Insert statement to enter them one row at a time, but let it cycle for as many rows as you have.

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ah yeah.. sorry I copied paste the wrong one.

 

$type = $_POST['tabledrop'];
$item = $_POST['name'];
$price = $_POST['price'];
$des = $_POST['description'];
$file = $_FILES['pbimage']['name'];



$query = "INSERT into $type SET {$type}_name = '$item' , {$type}_price = '$price' , {$type}_image = '$file' , {$type}_description = '$des' ";

 

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"You can ask the user how many items they wish to enter, then dynamically create that many form boxes, then just use a Insert statement to enter them one row at a time, but let it cycle for as many rows as you have."

 

From Rez

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right now, I have 3 items that needs to be stored into the database but only the last item gets stored and I think it's because my Insert codes is only run once so I am wondering if it's possible to run it 3 times so that all 3 items will be stored into the database instead of just the last 1.

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their information are to be stored and send to the inserting page but my insert page which looks like this ...

 

 

$type = $_POST['tabledrop'];
$item = $_POST['name'];
$price = $_POST['price'];
$des = $_POST['description'];
$feature = $_POST['feature'];
$file = $_FILES['pbimage']['name'];

$target_path = "C:/xampp/htdocs/paintball/itemimages/";
			$target_path = $target_path . basename( $_FILES['pbimage']['name']); 

			if(move_uploaded_file($_FILES['pbimage']['tmp_name'], $target_path)) {
   				 echo "The file ".  basename( $_FILES['pbimage']['name']). 
    			" has been uploaded/";

			}



$query = "INSERT into $type SET {$type}_name = '$item' , {$type}_price = '$price' , {$type}_image = '$file',{$type}_feature , {$type}_description = '$des' ";

$result = mysqli_query($link, $query) or die(mysqli_error($link));

 

 

can only store the last item , I'm thinking I'll need to use an array to go about sending all 3 items to this inserting page then through this inserting page , into my database.

 

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