andrej13 Posted January 21, 2011 Share Posted January 21, 2011 Hey guys I need some help for making some things work. This is my index.php and as you can see I have a table of my sql table and a drop list. Now when I press Add to chart on the table on my website, it goes to the cart. But when I select a item from the drop list and click on Add to chart, there only happens an increment of the quantity but the item does not go to the cart. http://fhcs.be/cart-demo2/index.php this is my website where you can check the problem out. Thanks Guys!!!! <?php // Include MySQL class require_once('inc/mysql.class.php'); // Include database connection require_once('inc/global.inc.php'); // Include functions require_once('inc/functions.inc.php'); // Start the session session_start(); ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>PHP Shopping Cart Demo · Bookshop</title> <link rel="stylesheet" href="css/styles.css" /> </head> <body> <div id="shoppingcart"> <h1>Your Shopping Cart</h1> <?php echo writeShoppingCart(); ?> </div> <div id="booklist"> <h1>Books In Our Store</h1> <?php $sql = 'SELECT * FROM products ORDER BY id'; $result = $db->query($sql); $output[] = '<ul>'; while ($row = $result->fetch()) { $output[] = '<li>"'.$row['name'].': €'.$row['price'].'<br /><a href="cart.php?action=add&id='.$row['id'].'">Add to cart</a></li>'; } $output[] = '</ul>'; echo join('',$output); ?> <? $Link = mysql_connect("fhcs.be.mysql","fhcs_be","xxxx"); $Query = "SELECT * FROM products"; $DBName = "fhcs_be"; $results = mysql_db_query($DBName, $Query, $Link); ?> Select a name <select name = "drop1" size="1"> <Option Value=" ">Select One:</option> <? //Begins PHP for($u=0;$u<mysql_num_rows($results); $u++) { $ID=mysql_result($results,$u,'name'); ?> <option value="<? echo($ID); ?>"><? echo($ID); ?></option><? //Begins PHP //Begins PHP } ?> </select> <? //Begins PHP if (mysql_db_query ($DBName, $Query, $Link)) { } else { print ("FAILURE<BR>\n"); } mysql_close ($Link); ?> </div> </body> </html> Quote Link to comment Share on other sites More sharing options...
Maq Posted January 21, 2011 Share Posted January 21, 2011 (I put tags around your code, please use them next time) Quote Link to comment Share on other sites More sharing options...
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