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echo Day


unemployment

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How do I echo the day from the db? It just displays day and I want it to display the day that was set.

 

<select name="date_of_birth" id="date_of_birth">
				<option value="">Day</option>
				<?php 

				$isset = isset($_POST['date_of_birth']);

				for($day = 1; $day <= 31; ++$day)
				{
					echo '<option';

					if ($isset && $_POST['date_of_birth'] === $day)
					{
						echo ' selected="selected"';
					}

					echo ">${day}</option>\n\t\t\t\t\t\t";
				}

				?>
			</select>

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Wouldn't it be

 

<select name="date_of_birth" id="date_of_birth">
				<option value="">Day</option>
				<?php 

				$isset = isset($_POST['date_of_birth']);

				for($day = 1; $day <= 31; ++$day)
				{
					echo '<option';

					if ($isset && $_POST['date_of_birth'] === $day)
					{
						echo ' selected="selected"';
					}

					echo ">{$day}</option>\n\t\t\t\t\t\t"; // Your dollar sign was outside the braces
				}

				?>
			</select>

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Agree with above re:no db reference; however, might try...

<select name="date_of_birth" id="date_of_birth">
<option value="">Day</option>
<?php 
$isset = isset($_POST['date_of_birth']);
for($day = 1; $day <= 31; $day){
?>
<option value="<?PHP echo $day; ?>"
<?PHP
if ($isset && $_POST['date_of_birth'] === $day){
	echo ' selected="selected"';
}
echo ">" . $day . "</option>\n\t\t\t\t\t\t";
}
?>
</select>

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