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Having a problem formatting a date


jeffkas

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Hi all.. 

I'm grabbing the following date format from an rss feed: 

Sun, 16 Jan 2011 00:00:00 -0800

 

What's the best way to strip away the first 5 characters (Sun, ) and the last 15 characters ( 00:00:00 -080)... but still keeping this as a date (not a string) to store in my database? 

 

Thanks in advance for any ideas!

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probably substr

 

 

the last 15

$date="Sun, 16 Jan 2011 00:00:00 -0800"; 
$date=substr($date,-15);   /// this would give you "Sun, 16 Jan 2011"
$date=substr($date,0,5); //  "16 Jan 2011" 
$timestamp=strtotime($date); 

then you can format it and do whatever you want from there

$formatted_date=date("Y-m-d", $timestamp);  // 2011-01-16 

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Well my code was much like the first reply.  I thought I was doing something wrong but apparently that's not the problem.  I have a very strange oddity.  My code is this:

$date = substr($date, 6, 18);
$date = strtotime($date);
$date = date( 'y-m-d', $date );

 

But...  I can't for the life of me figure out why I can't capture any double-digit day for 2011!  I'm grabbing contents for the last 2 months.. the rss feed has plenty of dates from 10 - 31, and they're saved for December in mysql, but mysql replaces any January day of 10 till now with a zero... so 11 becomes 01, 12 becomes 02, etc...

 

Anyway.. thanks for the help.  Not much you can do for my other issue without seeing code.  I'm just venting.  :) 

 

Thanks! 

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strtotime will take that whole mess and parse it without issue . . .

 

$date="Sun, 16 Jan 2011 00:00:00 -0800";
$formatted_date=date("Y-m-d", strtotime($date));
echo $formatted_date; // 2011-01-16

 

 

IT WORKED!!  Thank You!!  I cannot figure out why the other code wouldn't.. sure looks like it should, but I tried this before hanging it up for the day and voila!

$date=date("Y-m-d", strtotime($date));

 

I can't believe that's smart enough to strip the string like that.  Love it!  Thanks again! 

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