Users who re-visit in less than 48 hours.

This must be less complex than what it sounds like.

I want to find out the users that have logged in my page in LESS THAN 48 hours in the first trimester of last year. And place them in another table.

My MySql DB has a table with "user id" and "date" fields.

I have sorted out users that have visited only once in that trimester, leaving only duplicates: with repeating "userid" but with different "date".

I have spent days now trying to figure out how to use de date_diff function to solve this. My date format is d/m/y.

Please help with code!

Thank you.

(excuse my english)

Add a `visted` column and update their time on each refresh by adding it to the template to update their row.  Then just grab the SQL table WHERE `visited` > $time when $time = time() - (48 * 60 * 60);

Or even better, use the native MySQL time manipulation functions.

SELECT `record` FROM `table` WHERE `datetime_field` > ( DATE_SUB(NOW(), INTERVAL 48 HOURS) )

Pikachu2000: Your solution is very helpful if MySqls allow_invalid_dates function would work. Remember my format is dd/mm/yy. It converted my dates to 0000-00-00.

Unless there is a function I am unaware of. i believe this option is discarded.

Kira: I´m burning my neurons using your solution here, and I think it will work. I am sure as a beginner in PHP I can figure it out.

Thanks for the help! I´ll post updates on my progress.

I didn't notice the format, but why not convert the dates to a valid format and store them in the proper field type?

I didn't notice the format, but why not convert the dates to a valid format and store them in the proper field type?

Ha! Because I have no idea how to. I am looking it up right now, to see how! Thanks.