echo html in php

[fife]

Hi im trying to echo out some html within php based on an if statement.  Basically if you the is part of a club within a list item list the clubs, if they are not echo none within the list.  Here is the code and below will be the error from the server.

   <?php 
					// Query for finding out if the signed in user is part of any clubs and then display them here.
					$qMyClub = "SELECT clubID, name FROM clubs WHERE memberID = ".$User['memberID']."";
					$rMyClub = mysql_query($qMyClub);
					$NumClubs = mysql_num_rows($rMyClub);
					if ($NumClubs>=1) { 
					 while($Clubs = mysql_fetch_assoc($rMyClub)){
					  echo"<li>My Clubs
                        	<ul>
                            <li><a href=\"members/myclub.php?club='$Club['clubID']'\">$Club['name']</a></li>
                            </ul>
                        </li>";						 
					}
					else ($NumClubs==0) {

					echo"
					 <li>My Clubs
                        	<ul>
                            <li>None</li>
                            </ul>
                        </li>";	
					}
					 }
                        ?>

and the error;

 

[error] [client ] PHP Parse error:  syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /home/sites/index.php on line 78, referer:

 

its referencing to the following line;

<li><a href=\"members/myclub.php?club='$Club['clubID']'\">$Club['name']</a></li>

 

I dont understand php enough to fix this can anyone help?

 

 

 

 

 

 

 

 

 

 

 

 

[Pikachu2000]

Enclose your array elements in curly braces: {$array['element']}

[fife]

thank you but now the error has moved down a few lines;

 

PHP Parse error:  syntax error, unexpected T_ELSE in /home/sites/yourarena.co.uk/public_html/members/index.php on line 82, referer:

// Query for finding out if the signed in user is part of any clubs and then display them here.
					$qMyClub = "SELECT clubID, name FROM clubs WHERE memberID = ".$User['memberID']."";
					$rMyClub = mysql_query($qMyClub);
					$NumClubs = mysql_num_rows($rMyClub);
					if ($NumClubs>=1) { 
					 while($Clubs = mysql_fetch_assoc($rMyClub)){
					  echo"<li>My Clubs
                        	<ul>
                            <li><a href=\"members/myclub.php?club='{$Club['clubID']}'\">{$Club['name']}</a></li>
                            </ul>
                        </li>";						 
					}
					else ($NumClubs=0) {
					echo"
					 <li>My Clubs
                        	<ul>
                            <li>None</li>
                            </ul>
                        </li>";	
					}
					 }

 

it means this line

else ($NumClubs==0) {

 

I tried changing it to just one = but nothing

[Pikachu2000]

Your while loop's closing curly brace seems to be missing, and it appears you're trying to use elseif() syntax with an else{}.

[litebearer]

Perhaps...

 

<?PHP
// Query for finding out if the signed in user is part of any clubs and then display them here.
$member_id = $User['memberID'];
$qMyClub = "SELECT clubID, name FROM clubs WHERE memberID = $member_id'";
$rMyClub = mysql_query($qMyClub);
$NumClubs = mysql_num_rows($rMyClub);
if ($NumClubs>=1) { 
	?>
	My Clubs<br>
	<ul>
	<?PHP
	while($Clubs = mysql_fetch_assoc($rMyClub)){
		?>
		<li><a href="members/myclub.php?club=<?PHP echo $Club['clubID']; ?>"><PHP echo $Club['name']; ?></a></li>
		<?PHP
	}
	<?PHP
	</ul>
	<?PHP
}
}else{
?>
My Clubs<br>
<ul>
<li>None</li>
</ul>
<?PHP
}
?>