lucan Posted February 22, 2011 Share Posted February 22, 2011 Dear all PHP experts need your help please as I'm very new the PHP. I found this php form script on the net which works perfectly but only uploads one file. I need to upload a second file and send it to a different folders and a different field on the database. I have viewed a number of site and changed the code a number of time without success I have put the code back to original script, can some one please show me what I need to do. Thanks <form action="upload.php" method="post" enctype="multipart/form-data"> <label>First Name</label><input type="text" name="fname" /><br /> <label>Last Name</label><input type="text" name="lname" /><br /> <label>Upload Image</label> <input type="file" name="image" /><br> <label>Spec</label> <input type="file" name="spec" /><br /> <input type="hidden" name="MAX_FILE_SIZE" value="100000" /> <input type="submit" id="submit" value="Upload" /> </form> Script function is_valid_type($file) { $valid_types = array("image/jpg", "image/jpeg", "image/bmp", "image/gif"); if (in_array($file['type'], $valid_types)) return 1; return 0; } function showContents($array) { echo "<pre>"; print_r($array); echo "</pre>"; } $TARGET_PATH = "images/"; $fname = $_POST['fname']; $lname = $_POST['lname']; $image = $_FILES['image']; $fname = mysql_real_escape_string($fname); $lname = mysql_real_escape_string($lname); $image['name'] = mysql_real_escape_string($image['name']); $TARGET_PATH .= $image['name']; if ( $fname == "" || $lname == "" || $image['name'] == "" ) { $_SESSION['error'] = "All fields are required"; header("Location: index.php"); exit; } if (!is_valid_type($image)) { $_SESSION['error'] = "You must upload a jpeg, gif, or bmp"; header("Location: index.php"); exit; } if (file_exists($TARGET_PATH)) { $_SESSION['error'] = "A file with that name already exists"; header("Location: index.php"); exit; } if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { $sql = "insert into people (fname, lname, filename,spec) values ('$fname', '$lname', '" . $image['name'] ."')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); header("Location: images.php"); exit; } else { $_SESSION['error'] = "Could not upload file. Check read/write persmissions on the directory"; header("Location: index.php"); exit; } Quote Link to comment Share on other sites More sharing options...
cssfreakie Posted February 22, 2011 Share Posted February 22, 2011 i have no idea how to do that, but I do know is that most people love it when you post your code in [code]tags Quote Link to comment Share on other sites More sharing options...
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