andrej13 Posted March 8, 2011 Share Posted March 8, 2011 As you can see, my array contains drinks $dranken = array("cola", "fanta", "bier", "koffie", "thee"); but how can I call the drinks up from an sql table instead of typing them in like I did now? <?php if (!isset($_POST['submit'])) { ?> <html> <form method="post" action="<?php echo $PHP_SELF; ?>"> <?php $dranken = array("cola", "fanta", "bier", "koffie", "thee"); $prijzen = array("2", "2", "1.80", "2.20", "2.20"); $i = 0; echo "<table>"; while ($dranken[$i]) { $listnaam = $dranken[$i] . "_aantal"; $optionlist = "<select name= '$listnaam'><option>0</option><option>1</option><option>2</option><option>3</option></select>"; echo "<tr><td >" . $dranken[$i] . "</td>"; echo "<td>" . $optionlist . "</td>"; echo "<td>" . $prijzen[$i] . "</td></tr>"; $i++; } echo "</table>"; ?> <input type="submit" value="Toon Output" name="submit"/> </form> <?php } $dranken = array("cola", "fanta", "bier", "koffie", "thee"); $prijzen = array("2", "2", "1.80", "2.20", "2.20"); $i = 0; $totaalPrijs = 0; while ($dranken[$i]) { $aantal = $_POST[$dranken[$i] . "_aantal"]; if ($aantal > 0) { $prijsperDrank = $aantal * $prijzen[$i]; echo $dranken[$i] . ":" . $aantal . "Prijs:" . $prijsperDrank . "</br>"; $totaalPrijs += $prijsperDrank; echo "totaal: $totaalPrijs"; } $i++; } ?> </html> Quote Link to comment Share on other sites More sharing options...
Riparian Posted March 8, 2011 Share Posted March 8, 2011 try this <?php // connect to your database $DrinkArray=array() ; $DrinkResult=mysql_query("select flavour from drinks ")or die(mysql_error()); while($DrinkRow=mysql_fetch_assoc($DrinkResult)){ $DrinkArray[]=$DrinkRow[flavour]; } //check your output with something like this foreach($DrinkArray as $value){ echo $value.'<br />'; } ?> Quote Link to comment Share on other sites More sharing options...
andrej13 Posted March 9, 2011 Author Share Posted March 9, 2011 without succes Quote Link to comment Share on other sites More sharing options...
Riparian Posted March 10, 2011 Share Posted March 10, 2011 What I have put here is correct ... obviously you have to change the mysql_query("select flavour from drinks ") and $DrinkArray[]=$DrinkRow[flavour]; to suit your table contents... Afraid I only speak English Quote Link to comment Share on other sites More sharing options...
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