pcw Posted March 16, 2011 Share Posted March 16, 2011 Hi, I have this script which does what it is meant to do. I have assigned session_id() to the variable $sid so I can use it when logging in to a users account, however I get this error. How do I get around this? Warning: Unknown: Your script possibly relies on a session side-effect which existed until PHP 4.2.3. Please be advised that the session extension does not consider global variables as a source of data, unless register_globals is enabled. You can disable this functionality and this warning by setting session.bug_compat_42 or session.bug_compat_warn to off, respectively. in Unknown on line 0 As this is going to be installed on many servers, I do not want to have to edit the php.ini file on each one so as not to get this error. Is there an alternative way to assign the session_id() as so $sid = session_id(); so this doesnt happen? <div id="pageNav"> <div id="sectionLinks"> <a href="admin.php?cmd=manage1&username=admin">Manage</a> <a href="admin.php?cmd=dashboard&username=admin">Dashboard</a> <a href="admin.php?cmd=msgcenter&username=admin">Message Center </a> <a href="admin.php?cmd=manage&username=logins">Logins</a> </div> </div> <div id="content"> <div class="page"> <table width="100%" border="1" align="center"> <td bgcolor="#99FF66"><div align="center"><span class="style3">Login</span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Name</span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Registration Date </span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Approved </span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Reset Password </span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Delete</span></div></td> </tr> <?php session_start(); $sid = session_id(); session_register('sid'); include_once("data/mysql.php"); $mysqlPassword = (base64_decode($mysqlpword)); $db = mysql_connect("$localhost", "$mysqlusername", "$mysqlPassword") or die ("Error connecting to database"); mysql_select_db("$dbname", $db) or die ("An error occured when connecting to database"); $result = mysql_query("SELECT * FROM members"); while($row = mysql_fetch_assoc($result)){ echo "<tr><td><a href=templates/members/home.php?username=".$row['username']."&sid=$sid>".$row['username']."</a></td> <td>".$row['firstname']." ".$row['lastname']."</td> <td>".$row['registration_date']."</td> <td><a href=admin.php?cmd=approval&username=".$row['username']."&approved=".$row['approved'].">".$row['approved']."</a></td> <td><a href=templates/members/changepw.php?username=".$row['username']."&sid=$sid>Change Password</a></td> <td><a href=templates/members/delete.php?username=".$row['username']."&sid=$sid>Delete</a></td></tr>"; } ?> </div> </div> </div> <tr> <td> </td> <td> </td> <td> </td> <td> </td> <td> </td> <td> </td> </tr> </table> </div> </div> </div> Many Thanks Paul Quote Link to comment Share on other sites More sharing options...
facarroll Posted March 16, 2011 Share Posted March 16, 2011 Place these lines just so, at the beginning of your file. <?php session_start(); ini_set('session.bug_compat_42',0); ini_set('session.bug_compat_warn',0); Quote Link to comment Share on other sites More sharing options...
pcw Posted March 16, 2011 Author Share Posted March 16, 2011 Thankyou so much facarroll, yr a star Quote Link to comment Share on other sites More sharing options...
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