retrieve value from 3 dropdown menus which are the same name?

[zac1987]

I have 3 dropdown menus which have the same name <select name="dropdown">, how to get the value from 3 of them by using php for loop and array? I did try to put array on them before, but seem it can't work. My codes :

 

<?php

for ( $counter = 1; $counter <= 3; $counter ++) {

if (isset($_POST['submit'])) { //Form has been submitted.

$dropvalue = $_POST['dropdown[$counter]'];

        echo $dropvalue;

}

}

?>

 

<form action="test8.php" name="frmtest8" method='post'>

<select name="dropdown[1]">

<option value="1st">first</option>

    <option value="2nd">second</option>

    <option value="3rd">third</option>

</select>

 

 

<select name="dropdown[2]">

<option value="1st">first</option>

    <option value="2nd">second</option>

    <option value="3rd">third</option>

</select>

 

<select name="dropdown[3]">

<option value="1st">first</option>

    <option value="2nd">second</option>

    <option value="3rd">third</option>

</select>

 

<input type="submit" name="submit"  value="Send" />

</form>

 

It gives error message Parse error: parse error in C:\wamp\www\plekz\test8.php on line 23

 

I guess the error is because of $_POST['dropdown[$counter]']; I cannot put the two symbols [] inside  $_POST[' '] right? How to call the array if cannot put the two symbols?

[PFMaBiSmAd]

The $_POST variables will be - $_POST['dropdown][1], $_POST['dropdown][2], and $_POST['dropdown][3]

 

You would typically use a foreach() loop -

 

foreach($_POST['dropdown] as $key => $value){
    // $key will be 1,2, or 3
    // $value will be the submitted value
}

[zac1987]

@PFMaBiSmAd , your code works like charm. Thank you. 

[zac1987]

May I ask another question?

 

Note that 3 of my dropdown menu has array on its name, eg : <select name="dropdown[1]">

 

 

$query2 = "SELECT * FROM messages";

$result2 = mysql_query($query2,$connection) or die (mysql_error());

confirm_query($result2);

while($userinfo = mysql_fetch_array($result2)){

                              echo "<select name=\"dropdown[]\">";

                        }

 

If I have 10 rows of records on the database, I want the php auto creating 10 dropdown menus with the name=dropdown[1] to dropdown[10], how to do that? Is it I need to use for loop $i = 1, $i <=10, $i++ then put name=dropdown[$i] ? But if I put the for loop inside the while loop, it will create 30 dropdown menus, seriously I don't know how to do that...

                       

Or can I do something like this?

$count=0;

while($userinfo = mysql_fetch_array($result2)){

                              $count=$count + 1;

                              echo "<select name=\"dropdown[$count]\">";

                        }