swincher4391 Posted May 6, 2011 Share Posted May 6, 2011 Here are the project of files: So the problem I'm running into is, while php ---> php is fine (it's recovering all of my variables, I've tested with echo), the problem seems to be where I have made a command ./createlisting.sh $itemno $title $header $description $image It reads in $itemno, $title, $header $description just fine, but it fails when I try to send an image. Again I've echoed it out and my $image variable contains the correct image name. When it gets sent to the bash script and the bash script sends it to a "log.txt" it only shows $1 thru $4, excluding the $5. When I try to use the img src to create the image on the page, the outputting echo on the page is <img src ="/images/" /> Which of course is going to result in nothing. What advice can you guys offer me? Thanks! createPage.php: <html> <body> <form enctype="multipart/form-data" action="submitForm.php" method="post"> Item#: <input type="text" name="itemno" value="1" /><br /> Title: <input type="text" name="title" value="My Listing" /><br /> Header: <input type="text" name="header" value="ENTER YOUR LISTING" /><br /> <textarea name="description" cols="60" rows="20"> You will have to use quotes on anything that has more than one word. Sorry! </textarea><br><br /></p> <input type="hidden" name="MAX_FILE_SIZE" value="100000" /> Choose an image to upload: <input name="uploadedfile" type="file" /><br /> <input type="submit" value="Submit" /> </form> </body> </html> submitForm.php: <?php $itemno = $_POST["itemno"]; $title = $_POST["title"]; $header = $_POST["header"]; $description = $_POST["description"]; // Where the file is going to be placed $target_path = "/home/images/"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); $image = basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } $command = "." . "/" . "createlisting.sh"; $param = $itemno . " " . $title . " " . $header . " " . $description; $finalimage = $image . ""; $final = $command . " " . $param . " " . $finalimage; passthru($final); createlisting.sh: #!/bin/bash #Create the page based on the information cd logs echo $1 > log.txt echo $2 >> log.txt echo $3 >> log.txt echo $4 >> log.txt echo $5 >> log.txt cd .. ./createNewDir.sh $(date +%m%d%Y) cd .. cd listings cd $(date +%m%d%Y) mkdir $1 cd $1 echo "<HTML>" > listing.html echo "<Head>" >> listing.html echo "<Title>" >> listing.html echo "$2" >> listing.html echo "</title>" >> listing.html echo "</head>" >> listing.html echo "<body>" >> listing.html echo "<h1>$3</h1><br>" >> listing.html echo "<img src=\"/images/$5\" />" echo "$4" >> listing.html echo "</body>" >> listing.html echo "</html>" >> listing.html cd .. cd .. cd .. cd scripts echo $(date +%d%m%Y); Quote Link to comment Share on other sites More sharing options...
wildteen88 Posted May 6, 2011 Share Posted May 6, 2011 Any reason why you're creating files with a bash script. PHP has many functions for reading/writing to files. Quote Link to comment Share on other sites More sharing options...
swincher4391 Posted May 6, 2011 Author Share Posted May 6, 2011 That's what I need help with. Not only do I need to create a different named file per each "listing" created, but I need to redirect the form info to format the page according to the way my bash script did. Please help. Quote Link to comment Share on other sites More sharing options...
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