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difference between Bar & &Bar


straygrey

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What is the difference between $foo = Bar::getInstance(), and $foo = &Bar::getInstance(), assuming Bar::getInstance() returns an instance of the class named “Bar”?

Does &Bar return the address of rather than the instance?

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That syntax should not be used.  Back in the PHP4 days, the way objects were passed required the use of & in many cases, but in PHP5 all objects are passed by reference.  In PHP there aren't really pointers, but the general idea is the same -- making a copy of a data structure vs. using the actual data structure.  Objects are automatically passed by reference now.

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