second picture goes out of <tr>

Looks like HTML problem. But can not put this question in HTML section cause it has PHP code.

I have table. I have 3 rows. 1 of rows has rowspan with 2 other rows.Problem is when database is empty program should take one picture and put inside 2 cells of table. First picture sits inside td normally but second picture not fitting into td and gows out of <tr>. Do not know what to do.

echo "<tr>

  <td rowspan='2' width='1000' height='600'>

    <div id='fadeshow1'></div>

  </td>

  <td valign='top' height='300' background='tilbud.jpg'>";

    if(!mysql_num_rows($result)){

      echo "<img src='note.jpg'>";

    }else{

    echo "<table border='1' width='120' style='table-layout:fixed' cellspacing='0'>

      <tr><td colspan='2'><center><b>Ukens tilbud</b></center><br></td></tr>";

      while($row = mysql_fetch_array($result)){

        echo "<tr><td>";

        $product = $row["Product"];

        $price = $row["Price"];

        echo "$product";

        echo "</td>";

        echo "<td>" . "$price" . "</td></tr>";

      }

    }

    echo "</table></td></tr>";

$query = "SELECT Product, Price FROM tilbud WHERE Period='Daglig'";

$result = mysql_query($query,$link_id) or die (mysql_error());   

echo "<tr background='tilbud.jpg'>

      <td valign='top' height='300' width=120 background='tilbud2.jpg'>";

      if(!mysql_num_rows($result)){

      echo "<img src='note.jpg' width='120'>";

      }else{

        echo "<table border='1' width='120' style='table-layout:fixed' cellspacing='0'>

                <col width=110>

                <tr><td colspan=2><center><b>Dagens tilbud</b></center><br></td></tr>";

                while($row = mysql_fetch_array($result)){

                  echo "<tr><td  width='110'>"; 

                  $product = $row["Product"];

                  $price = $row["Price"];

                  echo "$product"; 

                  echo "</td>";

                  echo "<td>" . "$price" . "</td></tr>";

                }

              echo "</table>";

      }

echo "</td></tr>

might be because you forgot to encase one of your attributes in quotes...this

<td valign='top' height='300' width=120 background='tilbud2.jpg'>";

needs to be changed to this

<td valign='top' height='300' width='120' background='tilbud2.jpg'>";

Thanks fugix for reply. I modified code as you said. Still the same thing. One <td> do not fit into <tr> and goes down.

I even decreased width and height of picture. It also doesn't help

One more note. When remove second <img> tag and write just echo "a"; it also writes letter a in another row.

if(!mysql_num_rows($result)){

      echo "a";

}

If your table is not displaying correctly it is probably due to your script outputting invalid HTML.

I have already found my own mistake.  Closing </table> tag is not in correct place :-)

echo "<tr>";

      if(!mysql_num_rows($result)){

        echo "<td valign='top' width='150' height='300' bgcolor='white' cellpadding='0'>";

        echo "<img src='note.jpg'>";

      }else{

        echo "<td valign='top' width='150' height='300' background='tilbud2.jpg' cellpadding='0'>

              <table border='0' width='150' style='table-layout:fixed' cellspacing='0'>

                <col width='120'>

                <col width='30'>

                <tr><td colspan=2><center><b>Dagens tilbud</b></center><br></td></tr>";

                while($row = mysql_fetch_array($result)){

                  echo "<tr><td>"; 

                  $product = $row["Product"];

                  $price = $row["Price"];

                  echo "$product"; 

                  echo "</td>";

                  echo "<td>" . "$price" . "</td></tr>";

                }

              echo "</table>";

      }

echo "</td></tr>

If your table is not displaying correctly it is probably due to your script outputting invalid HTML.

And if you get a totally useless reply to a question, what is that due to?