princeofpersia Posted May 16, 2011 Share Posted May 16, 2011 Hi guys I am doinga login form for an organization, this form has email, password and pin If user fills all the fields it will execute the query fine but if user doesnt enter the pin it will come up with an error, the issue is that this pin is not included anywhere in mysql_query I have. Query tries to get the company id from db and echo it out, so if I dont enter the pin I get the error I have echoes out and another system error which is Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in ..../Dashboard/index.php on line 35 and my line 35 is while($row=mysql_fetch_array($getpin)){ here is my code <?php include ('includes/db/db.php'); ?> <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-type" content="text/html; charset=utf-8" /> <title>Login | Careers Inbox Dashboard Admin</title> <link rel="stylesheet" href="./css/reset.css" type="text/css" media="screen" title="no title" /> <link rel="stylesheet" href="./css/text.css" type="text/css" media="screen" title="no title" /> <link rel="stylesheet" href="./css/form.css" type="text/css" media="screen" title="no title" /> <link rel="stylesheet" href="./css/buttons.css" type="text/css" media="screen" title="no title" /> <link rel="stylesheet" href="./css/login.css" type="text/css" media="screen" title="no title" /> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /></head> <body> <div id="login"> <h1>Dashboard</h1> <?php if (isset($_POST['login']) && $_POST['login']){ $email=addslashes(strip_tags($_POST['email'])); $in_password=addslashes(strip_tags($_POST['password'])); $pin=addslashes(strip_tags($_POST['pin'])); $password=md5($in_password); if (!$email || !$in_password || !$pin) echo "<div class='error'>Please fill all required fields</div>"; else $getpin=mysql_query("SELECT * FROM users WHERE UserEmail='$email' AND UserPassword='$password'"); while($row=mysql_fetch_array($getpin)){ $pin_email=$row['UserEmail ']; $pin_id=$row['UserId']; $pin_company_id=$row['company_id']; } echo "$pin_company_id"; } ?> <div id="login_panel"> <form action="" method="post" accept-charset="utf-8" /> <div class="login_fields"> <div class="field"> <label for="email">Email</label> <input type="text" name="email" value="" id="email" tabindex="1" placeholder="email@example.com" /> </div> <div class="field"> <label for="password">Password <small><a href="forgotpassword.php">Forgot Password?</a></small></label> <input type="password" name="password" value="" id="password" tabindex="2" placeholder="password" /> <div class="field"> <label for="pin">Pin Number</small></label><input type="password" name="pin" value="" id="password" tabindex="2" placeholder="pin"/> </div> </div> </div> <!-- .login_fields --> <div class="login_actions"> <input type="submit" name="login" value="Login" class="btn btn-grey"/> </div> </form> </div> <!-- #login_panel --> </div> <!-- #login --> </body> </html> thank you in advance. Quote Link to comment Share on other sites More sharing options...
fugix Posted May 16, 2011 Share Posted May 16, 2011 seems like your else statement is not getting triggered..therefore your mysql_fetch_array() function is trying to use an empty var Quote Link to comment Share on other sites More sharing options...
princeofpersia Posted May 16, 2011 Author Share Posted May 16, 2011 so what do u think i should do? Quote Link to comment Share on other sites More sharing options...
princeofpersia Posted May 16, 2011 Author Share Posted May 16, 2011 found the solution, I have brackets for my else statement now, thanks for you time Quote Link to comment Share on other sites More sharing options...
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