MjM8082 Posted August 23, 2011 Share Posted August 23, 2011 Have never done this before, but I'm sure many of you have. What I am trying to do is take the information that the user fills out in this form and when they hit submit, it will be displayed into a html table on the next page. I don't need someone to do the entire table for me, just looking for some help to get started and a general idea of what to do. Here is my code for my form that I have created... <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Lab 4</title> </head> <body> <?php ?> <form method="POST" action="lab4form.php"> <label for="first_name">First Name:</label> <input type="text" id="first_name" name="first_name" /><br /> <label for="last_name">Last Name:</label> <input type="text" id="last_name" name="last_name" /><br /> <label for="coverage_amount">Coverage Amount:</label> <input type="text" id="coverage_amount" name="coverage_amount" /><br /> <label for="gender">Gender:</label> <br> <input id="male" type="radio" value="radiobutton" name="male" /> <label for="male">Male</label> <input id="female" type="radio" value="radiobutton" name="female" /> <label for="female">Female</label> <br /> <br> <label for="Age">Age:</label> <input type="text" id="age" name="age" /><br /> <br> <label for="health">Health Conditions</label> <br /> <input type="checkbox" name="health" value="heart" /> <label for="health">Heart Disease</label><br /> <input type="checkbox" name="health" value="diabetes" /> <label for="health">Diabetes</label><br /> <input type="checkbox" name="health" value="blood" /> <label for="health">High Blood Pressure</label><br /> <input type="checkbox" name="health" value="Smoker" /> <label for="health">Smoker</label><br /> <input type="checkbox" name="health" value="lung" /> <label for="health">Lung disease</label><br /> <FORM METHOD=POST ACTION="lab4form.php"> <P>Employment Status<BR> <SELECT NAME="employment"> <OPTION VALUE="lab4form.php">Unemployed <OPTION VALUE="lab4form.php">Full-Time <OPTION VALUE="lab4form.php">Part-Time <OPTION VALUE="lab4form.php">Student </SELECT><br /> <br> <label for="comments">Comments</label> <input type="text" id="comments" name="comments"/><br /> <br> <input type="submit" value="Add User" name="btn_add" /> </form> </body> </html> Quote Link to comment Share on other sites More sharing options...
doddsey_65 Posted August 23, 2011 Share Posted August 23, 2011 in your next page use something like <table> <tbody> <tr> <td> <?php echo $_POST['first_name']; ?> </td> the rest should be self explanitory. Quote Link to comment Share on other sites More sharing options...
MjM8082 Posted August 23, 2011 Author Share Posted August 23, 2011 Thank you, and when I get to something like.. The check boxes and radio buttons on the form, how do I get those to display on the table? For example... Gender on the form is selected by a radio button. How would I get the correct radio button that is click on to display on the next page on the table? Quote Link to comment Share on other sites More sharing options...
WebStyles Posted August 23, 2011 Share Posted August 23, 2011 same thing: <input type="radio" name="gender" value="Male" /> <input type="radio" name="gender" value="Female" /> On the next page, use: echo $_POST['gender']; Quote Link to comment Share on other sites More sharing options...
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