Jump to content

!HELP! Popup window like facebook photos


phpnewbei

Recommended Posts

I need help with my webpage here, how do you get so if you are at http://www.blabla.com/account.php and then click on a photo, it will go to www.blabla.com/photo.php?id=1 but still be at account.php? Just like facebook shows their photos. I dont know how to think nor to get it work. Would appreciate some help!

 

ThNXX 1n 4dv4nc3 // Machram!

Link to comment
Share on other sites

Thanks for a fast reply! That was what I was looking for, but do you know if I can use MySQL commands in there also? Cuz it's pretty much needed :) I'm going to use it for a photo that you can choose to make as profile picture :P

 

In the meantime, i'll try to fix it on my own!

 

Thanks in advance! / Machram

Link to comment
Share on other sites

I don't go on Facebook very often (or are even able to access it at this moment), but somewhere in the URL they will have a hash. The hash allows you to alter the address without actually navigating away from the page. Only newer browsers support an event to to detect said changes, but there's a jQuery plug-in available that will make it all effortless, and also allow you to support the back-button navigation.

 

Just note that whatever appears in the hash is not sent to the web server - i.e. you can't get the value of it within PHP.

Link to comment
Share on other sites

If it was to just open up a large picture you wouldn't need 'SQL commands' within the said window...

 

although if it was a specific persons profile picture just to enlarge you could get the image from the database and just put it in the path:

 

off the top of the head i can't remember exactly how to reference orange box but you would do this to get your picture (only as an example)

 

$sql = 'SELECT image FROM profiles WHERE username "' . $_GET['userid'] . '"';

 

// userID would be in the query string in the URL

 

// fetch the array from the SQL

$row = mysql_fetch_array($sql);

 

and this would be the html for the image tag to actually call in your own image from database...

 

<img src="/path/images/<?= $row['image']; ?>" >

Link to comment
Share on other sites

phpnewbei, i know what you are trying to do. you want to do a fanybox/lightbox something similar to facebook photo view and the url changes to the photo url with the page actually redirecting. i was also trying to achieve the same thing...

 

Have a look at the jQuery plug-in I linked to.

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.