preg_replace woes

Evening all,

I'm looking to use preg_replace to change:

{{http://en.wikipedia.org/wiki/File:Wiki.png||wikipedia logo||This is the wikipedia logo}}

into

<figure><img src='http://en.wikipedia.org/wiki/File:Wiki.png' alt='wikipedia logo' /><figcaption>This is the wikipedia logo</figcaption></figure>

for example

so far i have

	$befor = array(); 
$befor[1] = "/({{)(.*?)(|)/";
$befor[2] = "/(|)(.*?)(|)/";
$befor[3] = "/(|)(.*?)(}})/";


$aftr = array();
$aftr[1] = "<figure><img src='$1'";
$aftr[2] = " alt='$2' />";
$aftr[3] = "<figcaption>$3</figcaption></figure>";


$content = preg_replace($befor, $aftr, $content);	

I'm obviously way out because it's just spitting out

alt='' /> alt='<' /> alt='' /> alt='f' />...etc

can anyone help me out?

Many thanks

Ian

<< Moved to Regex Forum >>

$input = "some text before {{http://en.wikipedia.org/wiki/File:Wiki.png||wikipedia logo||This is the wikipedia logo}} some text after";

$regex = "#{{([^|]*)\|\|([^|]*)\|\|([^|]*)}}#";
$replace = "<figure><img src='$1' alt='$2' /><figcaption>$3</figcaption></figure>";
$output = preg_replace($regex, $replace, $input);

echo $output;
//Output:
//some text before <figure><img src='http://en.wikipedia.org/wiki/File:Wiki.png' alt='wikipedia logo' /><figcaption>This is the wikipedia logo</figcaption></figure> some text after

That's much simpler,

Thanks a lot

Ian

I want to now reverse it. SO, I've got

$regex1 = '{{$1||$2||$3}}';								
$replace1 = '#<figure><img src="([^<]+)" alt="([^<]+)" /><figcaption>([^<]+)</figcaption></figure>#i';

$content = preg_replace($replace, $regex, $content);

but this isn't working. I must be near...

Any ideas?

Thanks

Ian

That makes absolutely no sense. What is in "$content" and what are you trying to search for and what are you wanting to replace it with?

Sorry, I've just replaced input and output from the previous example above with content. Either way I want to reverse the first situation so that my HTML turns into short hand:

{{http://en.wikipedia.org/wiki/File:Wiki.png||wikipedia logo||This is the wikipedia logo}}

That is a much, much different situation.

$regex = "#<figure><img src='([^']*)' alt='([^']*)' /><figcaption>([^']*)</figcaption></figure>#";
$replace = "{{$1||$2||$3}}";
$output = preg_replace($regex, $replace, $input);

for some reason

$replace = "{{$1||$2||$3}}";

is killing my script. I just get a blank page unless  I delete it.

Why would this be??

Ian

"{$" is interpreted as the start of a variable. Which, in this case, it is not. Thus PHP barfs.

Use single quotes or escape the $.

Hi Sorry to bang on about this but i'm still not having any luck with this.

$regex = "#<figure><img src='([^']*)' alt='([^']*)' /><figcaption>([^']*)</figcaption></figure>#";
$replace = "(($1**$2**$3))";
$pagecontent = preg_replace($regex, $replace, $pagecontent);

no curly brackets now and still won't preg_replace

any ideas?

Thanks folks

Ian

Hi Sorry to bang on about this but i'm still not having any luck with this.

You were already given the solution by requinix:

Use single quotes or escape the $.

Use single quotes

$replace = '{{$1||$2||$3}}';

or escape the dollar sign

$replace = "{{\$1||\$2||\$3}}";

I played about with it a bit more and found that in the $regex line i needed \ (slash) before the apostrophe.

so, here it is. thanks guys

$regex = '#<figure><img src="([^\']*)" alt="([^\']*)" /><figcaption>([^\']*)</figcaption></figure>#';
$replace = '{{$1||$2||$3}}';
$pagecontent = preg_replace($regex, $replace, $pagecontent);

I played about with it a bit more and found that in the $regex line i needed \ (slash) before the apostrophe.

Well, if you would have followed directions you wouldn't have had that problem. The regex I supplied was defined using double quotes around the string for a reason - so you wouldn't need to escape the single quotes inside the string.