Sleeper Posted November 4, 2011 Share Posted November 4, 2011 I have an issue with the below code if ($gtype == "%24L" || $gtype == "$L") The value actually starts with the dollar sign then L, but its being read as a variable that's not assigned so it showing as blank. so the question is how to I get to check and see if the value of gtype actually is $L in a way that it wont read $L as a variable and as a value instead? Quote Link to comment Share on other sites More sharing options...
PFMaBiSmAd Posted November 4, 2011 Share Posted November 4, 2011 Either escape the $ "\$L" or use single quotes - '$L' Quote Link to comment Share on other sites More sharing options...
Sleeper Posted November 4, 2011 Author Share Posted November 4, 2011 Well now I know I should just get some sleep. The escape is beginners mentality. I call brain fart..lol. Thanks. Now that its fixed im going to sleep..lol Quote Link to comment Share on other sites More sharing options...
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