Stalingrad Posted December 15, 2011 Share Posted December 15, 2011 Hey guys! I've looked through this code over and over today, and I still haven;t found where my error is. Here is my entire code: <?php session_start(); include("config536.php"); ?> <html> <head> <link rel="stylesheet" type="text/css" href="style.css" /> </head> <?php if(!isset($_SESSION['username'])) { echo "<banner></banner><nav>$shownavbar</nav><ubar><a href=login.php>Login</a> or <a href=register.php>Register</a></ubar><content><center><font size=6>Error!</font><br><br>You are not Logged In! Please <a href=login.php>Login</a> or <a href=register.php>Register</a> to Continue!</center></content>"; } if(isset($_SESSION['username'])) { echo "<nav>$shownavbar</nav><ubar>$ubear</ubar><content><center><font size=6>Quest Agency</font><br><br>"; $startjob = $_POST['submit']; $jobq = "SELECT * FROM jobs WHERE username='$showusername'"; $job = mysql_query($jobq); $jobnr = mysql_num_rows($job); if($jobnr == "0") { ?> <form action="<?php echo "$PHP_SELF"; ?>" method="POST"> <input type="submit" name="submit" value="Start Job"></form> <?php } if(isset($startjob)) { $initemidq = "SELECT * FROM items ORDER BY RAND() LIMIT 1"; $initemid = mysql_query($initemidq); while($ir = mysql_fetch_array($initemid)) { $ids = $ir['itemid']; } mysql_query("INSERT INTO jobs (username, item, time, completed) VALUES ('$showusername', '$ids', 'None', 'No')"); $wegq = "SELECT * FROM items WHERE itemid='$ids'"; $weg = mysql_query($wegq); while($wg = mysql_fetch_array($weg)) { $im = $wg['image']; $nm = $wg['name']; $id = $wg['itemid']; } $_SESSION['theid'] = $id; $yeshere = $_SESSION['theid']; echo "<font color=green>Success! You have started this Job!</font><br><br>Please bring me this item: <b>$nm</b><br><br><img src=/images/items/$im><br><br><br>"; } if($jobnr == "1") { $yeshere = $_SESSION['theid']; $finish = $_POST['finish']; $quit = $_POST['quit']; $okgq = "SELECT * FROM items WHERE itemid='$yeshere'"; $ok = mysql_query($okgq); while($ya = mysql_fetch_array($ok)) { $okname = $ya['name']; $okid = $ya['itemid']; $okimage = $ya['image']; } $yeshere = $_SESSION['theid']; echo "Where is my <b>$okname</b>?<br><br><img src=/images/items/$okimage><br><br><br>"; ?> <form action="<?php echo "$PHP_SELF"; ?>" method="POST"> <input type="submit" name="finish" value="I have the Item"><br><br> <input type="submit" name="quit" value="Quit"></form> <?php } } if(isset($finish)) { $yeshere = $_SESSION['theid']; $cinq = "SELECT * FROM uitems WHERE theitemid='$_SESSION[theid]'"; $cin = mysql_query($cinq); $connr = mysql_num_rows($cin); if($connr != "0") { mysql_query("DELETE FROM uitems WHERE username='$showusername' AND theitemid='$yeshere' LIMIT 1"); mysql_query("UPDATE users SET jobs=jobs+1 WHERE username='$showusername'"); mysql_query("UPDATE users SET credits=credits+320 WHERE username='$showusername'"); mysql_query("DELETE FROM jobs WHERE username='$showusername'"); echo "<font color=green>Success! You have completed this job! You have been given <b>320</b> credits as an award. Thank You!</font>"; } else { echo "<font color=red>Error! You do not have my item!</font>"; } if(isset($quit)) { mysql_query("DELETE FROM jobs WHERE username='$showusername'"); echo "<font color=green>Success! You have quit this quest.</font>"; } $yeshere = $_SESSION['theid']; } ?> The variable for the button is: $quit = $_post and I want the quit button to work. Does anybody know why it will not work? Thank you in advance! Quote Link to comment Share on other sites More sharing options...
PFMaBiSmAd Posted December 15, 2011 Share Posted December 15, 2011 Your form fields will be available as - $_POST['field_name'] variables. They will NOT be directly available as regular php variables - $field_name unless you have an assignment statement in your program - $field_name = $_POST['field_name']; Quote Link to comment Share on other sites More sharing options...
Stalingrad Posted December 15, 2011 Author Share Posted December 15, 2011 Cam you please re wrote what you just said? I'm not understanding it? ... I use them ALL if the time I'm not seeing how it's not working? Can you please show me how to use it in my code, thanks. Quote Link to comment Share on other sites More sharing options...
Shazer2 Posted December 15, 2011 Share Posted December 15, 2011 Shouldn't it be $_SERVER['PHP_SELF'] instead of $PHP_SELF? Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.