aianne Posted March 18, 2012 Share Posted March 18, 2012 Hello I am having a trouble with creating page that will search records from database using dropdown menu, when I select a category, for example By: Gender and after clicking the Submit button, there is no records displays but when I select By: ALL, the records displays. What's wrong with my code? I'm sorry I'm fairly new to PHP. Here is my code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title>Search</title> </head> <body> <form action="" method="POST" name="records"> <label>SEARCH: </label> <select name="select"> <option value="all" selected="selected">ALL</option> <option value="year">By Year</option> <option value="gender">By Gender</option> <option value="course">By Course</option> </select> <input name="submit" value="GO" type="submit" /> <br /> </form> </body> </html> <?php include('collegeinfo_connect.php'); mysql_connect("$server", "$user", "$pass")or die("cannot connect"); mysql_select_db("$db")or die("cannot select DB"); if (isset($_POST['submit'])) { $selection = $_POST['select']; if($selection == "all") $query = "SELECT * FROM collegeinfo_tbl"; else if($selection == "year") $query = "SELECT * FROM collegeinfo_tbl WHERE Year='year'"; else if($selection == "gender") $query = "SELECT * FROM collegeinfo_tbl WHERE Gender='gender'"; else if($selection == "course") $query = "SELECT * FROM collegeinfo_tbl WHERE Course='course'"; } if (isset($query)) { $result = mysql_query($query) or die(mysql_error()); echo "<br /> <br />"; echo "<table border='1' cellpadding='10'>"; echo "<tr> <th>ID Number:</th> <th>First Name:</th> <th>Last Name:</th> <th>Gender:</th> <th>Year:</th> <th>Course:</th> </tr>"; while ($row = mysql_fetch_array($result)) { echo "<tr>"; echo '<td>' . $row['ID'] . '</td>'; echo '<td>' . $row['FirstName'] . '</td>'; echo '<td>' . $row['LastName'] . '</td>'; echo '<td>' . $row['Gender'] . '</td>'; echo '<td>' . $row['Year'] . '</td>'; echo '<td>' . $row['Course'] . '</td>'; echo "</tr>"; } echo "</table>"; } ?> Quote Link to comment Share on other sites More sharing options...
Mahngiel Posted March 18, 2012 Share Posted March 18, 2012 $query = "SELECT * FROM collegeinfo_tbl WHERE Gender='gender'"; [/php[ Do you honestly have a row with this value 'gender'? More than likely you have a row for 'gender' but it's value is Male or Female. You'll need to either create chained dropdown selects that will give the option for male or female upon selecting 'by Gender', or you'll need to figure a new way to send the data you wish to receive. Quote Link to comment Share on other sites More sharing options...
aianne Posted March 18, 2012 Author Share Posted March 18, 2012 Oh! Yeah. You were right! Thanks man! I got it to work! Quote Link to comment Share on other sites More sharing options...
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