Jump to content

str_replace not working


chriscloyd

Recommended Posts

I am trying to make a presentation generator, using information from my database;

my str_replace is not working please help....

here is my code

<?php
$Sql = "SELECT * FROM csm_players WHERE uid = '{$this->Uid}'";
	$Query = mysql_query($Sql);
	$Style = $this->UserInfo['playerstyle'];
	while ($p = mysql_fetch_assoc($Query)) {
		$name = explode(" ",$p['name']);
		$PlayerName = (strpbrk($Style, '{FIRSTNAME}') ? str_replace("{FIRSTNAME}",$name[0],$Style) : "");
		$PlayerName1 = (strpbrk($Style, '{LASTTNAME}') ? str_replace("{LASTTNAME}",$name[1],$PlayerName) : "");
		$PlayerName2 = (strpbrk($Style, '{NICKNAME}') ? str_replace("{NICKNAME}",$p['nickname'],$PlayerName1) : "");
		if ($p['cl'] == 1) {
			if ($this->UserInfo['clba'] == 1) {
				$Show .= "<div>{$this->UserInfo['clstyle']} {$PlayerName}</div>";
			} else {
				$Show .= "<div>{$PlayerName} {$this->UserInfo['clstyle']}</div>";
			}
		} else {
			$Show .= "<div>{$PlayerName}</div>";
		}
	}
	//$Show .= "Error";
	return $Show;

 

this is what its returning

Shelton "{NICKNAME}" {LASTNAME} [CL]

Lindsey "{NICKNAME}" {LASTNAME}

Eitan "{NICKNAME}" {LASTNAME}

Aake "{NICKNAME}" {LASTNAME}

Hunter "{NICKNAME}" {LASTNAME}

 

if i take out the firstname search then it find the nickname and if i take out the nickname and the first it shows the last one.... what do i do?

i have tried to put them in an array and do a foreach with keys and val but that doesnt work either im at a standstill.  it works for my other script but not for this...

Link to comment
Share on other sites

Your final result after running all three replacements is stored in $PlayerName2 but your outputing $PlayerName, which only contains the result of the first replacement.

 

There's no need to use three separate variables, you can just re-use the same one.  You can also put your replacements in an array and do it in one call.

 

$replacements = array(
   '{FIRSTNAME}' => $name[0] ,
   '{LASTTNAME}' => $name[1],
   '{NICKNAME}' => $p['nickname']
);

$PlayerName = str_replace(array_keys($replacements), array_values($replacements), $Style);

Link to comment
Share on other sites

got it to work

<?php
public function getPlayers() {
	$Sql = "SELECT * FROM csm_players WHERE uid = '{$this->Uid}'";
	$Query = mysql_query($Sql);
	while ($p = mysql_fetch_assoc($Query)) {
		$Style = stripslashes($this->UserInfo['playerstyle']);
		$name = explode(" ",$p['name']);
		$array = array (
			"{FIRSTNAME}" => $name[0],
			"{LASTNAME}" => $name[1],
			"{NICKNAME}" => $p['nickname']
		);
		foreach ($array as $key => $val) {
			$Style = str_replace($key,$val,$Style);
		}
		if ($p['cl'] == 1) {
			if ($this->UserInfo['clba'] == 1) {
				$Show .= "<font size=\"1\">{$this->UserInfo['clstyle']} {$Style}</font><br>";
			} else {
				$Show .= "<font size=\"1\">{$Style} {$this->UserInfo['clstyle']}</font><br>";
			}
		} else {
			$Show .= "<font size=\"1\">{$Style}</font><br>";
		}
	}
	//$Show .= "Error";
	return $Show;
}

 

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.