How to make a image a link when it is outputted using PHP?

I basically have a PHP Search Form, and when a user fills in a form it outputs the results. Each result displays a image of a property, how could i make them images have their own unique link which will take them directly to the page of the property being shown?

Im using PHP and mySQL tables

Any help is appreciated,

Thank You.

Heres the PHP that outputs the results:

<?php
require_once 'mstr_ref.php';
function san($input){
if(get_magic_quotes_gpc()){
	$input=stripcslashes($input);
}
$output = mysql_real_escape_string($input);
return $output;
}
if(isset($_POST['submit'])){
$pVars = array('area'=>$_POST['areas'], 'propType'=>$_POST['prop_type'], 'saleType'=>$_POST['ptype'], 'minB'=>$_POST['min_bedrooms'], 'maxB'=>$_POST['max_bedrooms'], 'minP'=>$_POST['min_price'], 'maxP'=>$_POST['max_price']);
foreach ($pVars as $k=>$v){
	$v = san($v);
}
$sql = new makeQuery();
$sql->manAdd('location_id', $pVars['area']);
if($pVars['propType'] != 'Any'){
	$sql->manAdd('catagory_id', $pVars['propType']);
}
if ($pVars['maxB'] > 0){
	$sql->manAdd('bedrooms', $pVars['maxB'], '<=');
}
if($pVars['minB'] > 0){
	$sql->manAdd('bedrooms',$pVars['minB'],'>=');
}
if($pVars['saleType'] != 'Any'){
	if($pVars['saleType'] == "forsale"){
		$sql->manAdd('market_type', 'sale');
		if($pVars['minP'] != 0){
			$pVars['minP'] = $pVars['minP'] * 1000;
		}
		if($pVars['maxP'] != 0){
			$pVars['maxP'] = $pVars['maxP'] * 1000;
		}
	}
	if($pVars['saleType'] == 'forrent'){
		$sql->manAdd('market_type', 'rent');
	}
}

$qry = $sql->sqlStart.$sql->stmt.'Group By property.id';
$results = mysql_query($qry) or die (mysql_error()."<br />|-|-|-|-|-|-|-|-|-|-|-|-<br />$qry");
if(mysql_num_rows($results) < 1){
	die ("Sorry, No Results Match Your Search.");
}
while($row = mysql_fetch_assoc($results)){
	echo '<div class="container" style="float:left;">';
	echo '<div class="imageholder" style="float:left;">';
	echo "<img class='image1' src='{$row['image_path']}' alt='{$row['summary']}'> <br />";
	echo '</div>';
	echo '<div class="textholder" style="font-family:helvetica; font-size:14px; float:left; padding-top:10px;">';
	echo "{$row['summary']}";
	echo "<span style=\"color:#63be21;\"><br><br><b>{$row['bedrooms']} bedroom(s) {$row['bathrooms']} bathroom(s) {$row['receptions']} reception room(s)</b></span>";
	if($row['parking'] != null){
		echo "<span style=\"color:#63be21;\"><b> {$row['parking']} parking space(s)</b></span>";
	}

	echo '</div>';
	echo '<div style="clear:both"></div>';
}

}
else{
echo "There was a problem, please click<a href='index.php'> Here </a>to return to the main page and try again";
}
?>

You have

echo  "<a href="xxxx.com"><img class='image1' src='{$row['image_path']}' alt='{$row['summary']}'></a><br />";

What do you mean their own unique link

I mean when the results are displayed, they all will be different results on different properties. I have 9 properties on the website, therefore each property will have its own unique link to take them directly to the page that displays more information about the property.

That will just have the same link on all the results, but I need the different images to have different links?

Rough overview...

1. make each link to view.php passing  property id via url

2. make view.php page that: A) $_GET the id being passed; B) queries the db for that particular id; C) Displays the query results

Hi mate, I dont know much about PHP coding, could you break a down a little more? appreciate it.

echo "<a href='view.php?id=" . $row['id'] . "><img class='image1' src='{$row['image_path']}' alt='{$row['summary']}'></a> <br />";

view.php
<?php
GET the id
connect to db
query db for that paticular id
display the results
?>

So this will let me add different links on the different images of the properties?

Because I don't want anything to be displayed, Once the search results are displayed depending on the search made, I want the images to have their own unique links that will take them directly to the selected property page.

if each link has the unique property id corresponding to the image, then yes.

Thanks mate, where would the link be placed, for each image, in the database?

no, it will be where you want to display the images so the user can make their choice

Oh ok mate, i will give it a try and see what happens,

here what i have:

<?php
GET the id
define('__HOST', ''); //localhost = database host name (normaly this won't need changing)
define('__USER', '');    //xxx = database username
define('__PASS', '');    //xxx = database password
define('__DEF_DB', ''); //xxx = database name
query db for that paticular id
display the results
?>

Just another thing, I don't want the links to be displayed on the page, I just want the images to be links, so if the users click a image it will take them to another page.

Say you have a category table that has all your cats info including a column for the image location, we'll call it image_path.

run a sql statement to display the categories image_path and cat_id

while (this stuff) {

echo  '<a href="xxxx.com/category.php?cat='.$row['cat_id'].'"><img class="image1" src="'.$row['image_path'].' alt='.$row['summary'].'></a><br />';

}

Thanks for your assistance. Im a little bit confused, so do I create a field in my mySQL database and place the 'id' and the link then do the code you said?

echo  '<a href="xxxx.com/category.php?cat='.$row['cat_id'].'"><img class="image1" src="'.$row['image_path'].' alt='.$row['summary'].'></a><br />';
}

What would I put in "xxxx.com" because the links are going to all be different depending on which image is displayed.

What would I put in "xxxx.com" because the links are going to all be different depending on which image is displayed.

I was assuming you have a table like

cat_id | cat_name | summary | image_name |

1 | dogs | dogs are great |dogpic.jpg

2 | cat | cats are better | catpic.jpg

so xxxx.com/category.php?cat='.$row['cat_id']. would become  xxxx.com/category.php?cat=1 and it would be a picture of a dog and a link to the dog category.

It would look more like this if I did it

echo  '<a href="xxxx.com/category.php?cat='.$row['cat_id'].'"><img class="image1" src="/image-folder-path/'.$row['image_name'].'" alt='.$row['summary'].'></a><br />';

and your source would end up like this

<a href="xxxx.com/category.php?cat=1"><img class="image1" src="/image-folder-path/'docpic.jpg"' alt="dogs are great"></a><br />

here is a screenshot of my database: So here is the 'images' table, Could I add a field called 'url' or something then add the url in that field then somehow code it in php?

here is a screenshot of my database: So here is the 'images' table, Could I add a field called 'url' or something then add the url in that field then somehow code it in php?

I see you have your full path in the table so I'd used

echo  '<a href="xxxx.com/category.php?cat='.$row['cat_id'].'"><img class="image1" src="'.$row['image_path'].'" alt='.$row['summary'].'></a><br />';

but in my catagories i have types of property 'house' 'flat' There a image here showing you.

Could I put property id? because each property has its own unique id?

Could I put property id? because each property has its own unique id?

It lookes like you have two unique ids. You probably only need one.  Is id an auto_increment? Anyway as long as they're unique you can use them.

Okay we have

id | property_id | image_path

id | cat_name

so you could do

echo  '<a href="xxxx.com/category.php?cat='.$row['id or property_id'].'"><img class="image1" src="'.$row['image_path'].'" alt='.$row['cat_name or any column you want'].'></a><br />';

So now I have a url field in the images table, yeah the id is auto_increment.

Does that look right?

If I had only one pic per category I'd use something like

id | cat_name | image_path | url | summary or what ever  |

echo  '<a href="'.$row['url'].'"><img class="image1" src="'.$row['image_path'].'" alt="'.$row['cat_name/summary or any column you want'].'></a><br />';

or

echo  '<a href="'.$row['url'].'"><img class="image1" src="'.$row['image_path'].'" alt="'.$row['cat_name'].' - '.$row['summary or any column you want'].'></a><br />';