IOS version ?

Hi

I would like to know if I can show the actual version of ios on an iphone, ipod or ipad etc on a webpage. ?

I have a script that says if the actual iphone is on ios 5 and if not to show another message but I just wondered if there is a script to show iphone is running IOS 5.1.1 ?

<script type="text/javascript">

    if (navigator.userAgent.match(/OS 5(_\d)+ like Mac OS X/i))

        // this helps detect minor versions such as 5_0_1

        document.write("You have iOS 5! Aren't you special!");

</script>

<script type="text/javascript">

if (navigator.userAgent.match(/(iPad|iPhone);.*CPU.*OS 5_\d/i))

{

  alert("On iOS 5")

}

else

{

  alert("On iOS 4");

}

</script>

Thanks in Advance

The user agent exposes the version as say "5_1_1". How exactly do you want to fit this into your current script? Only detect 5.1.1, or detect 5 then 5.1.1?

Hi

I'd love the webpage to say if an iPhone went on the webpage for it to say

Your iPhone ios is 5.1.1

Or

Your iPad iOS is on 5.1.1

I can sort the windows version etc but struggling with ios

Thanks in advance

Martyn

Is there a specific reason you want to look for 5.1.1, functionality wise? Unless this is for some cool magic trick to tell the user what they already know (, or stats, though I don't know why you would be doing anything related to that client-side,) you'd be much better off using "feature detection" techniques, as opposed to parsing the user agent. What I mean by that is don't check what device they're on, check if a certain function/object/property/feature exists.

Have you looked into WURFL?

WURFL, the Wireless Universal Resource FiLe, is a Device Description Repository (DDR), i.e. a software component that maps HTTP Request headers to the profile of the HTTP client (Desktop, Mobile Device, Tablet, etc.) that issued the request.

Hi

I have a iPhone repair website and would just like to tell the user what ios version they are on and what the latest version is.

Saying wheather it's an iPod, iPhone or iPad would be great too.

I am open to other ways of getting the info if it's easier

Thanks again

Martyn